How can I adjust the pattern below to return true in cases like these:
m1, m1a, M100bc, s45, S396xyz
and return false in cases like these:
'', m, 1, 1a, mm, Mx, mm1, SS1b
The current pattern is: /^m\S\.*/i.test(text)
Currently, it matches any number of letters at the start and non-digits right after the first letter
Feel free to utilize
/^[a-z]\d.*/i
Take a look at the interactive regex demonstration. In case there could be line breaks in the string, simply swap out .* with [\s\S]*.
Specifics
^ - indicates the start of the string[a-z] - represents an ASCII letter\d - signifies a digit.* - denotes any zero or more characters other than line break characters ([\s\S] will match any characters).NOTE: Including .* (or [\s\S]*) at the end is recommended only if you require using the matched values. If not needed, you may exclude that portion of the pattern when utilizing RegExp#test().
One method to consider is testing only the first two characters.
var options = ['m1', 'm1a', 'M100bc', 's45', 'S396xyz', '', 'm', '1', '1a', 'mm', 'Mx', 'mm1', 'SS1'];
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