Decode the string containing indices inside square brackets and transform it into a JSON array

Question

Decode the string containing indices inside square brackets and transform it into a JSON array

I have a collection of strings that contain numbers in brackets like "[4]Motherboard, [25]RAM". Is there a way to convert this string into a JSON array while preserving both the IDs and values? The desired output should look like:

{"data":[
  {"id":"4","item":"Motherboard"},
  {"id":"25","item":"RAM"}
]};

I attempted using split(",") to parse the array but I am struggling to extract the inner data in this scenario.

javascript json split

Answer 1

Answer №1

To extract numbers and strings from a given text, you can utilize a regular expression to achieve this task. By applying the regex pattern on the input string, you can then store the extracted values as properties within an object.

var text = "[4]Motherboard, [25]RAM",
    dataArray = text.split(', ').map(function (item) {
        var result = item.match(/^\[(\d+)\](.+)$/);
        return { id: result[1], component: result[2] };
    });
console.log(dataArray);

Answer 2

To extract numbers and strings from a given text, you can utilize a regular expression to achieve this task. By applying the regex pattern on the input string, you can then store the extracted values as properties within an object.

var text = "[4]Motherboard, [25]RAM",
    dataArray = text.split(', ').map(function (item) {
        var result = item.match(/^\[(\d+)\](.+)$/);
        return { id: result[1], component: result[2] };
    });
console.log(dataArray);

Answer 3

Answer №2

Here's a simple way to accomplish this task using the pattern \[(\d+?)\](.+):

The (…) is a capture group, indicating that whatever matches within the brackets will be saved as a token.
\d represents a single digit.
\d+ means one or more digits in a row.
\d+? signifies one or more digits, but matching the fewest possible before moving on.
.+ matches any character at least once.

In regular expressions, [ and ] have special meanings, so if you want to include them literally, you must escape them like so: \[ and \].

The double backslashes \\ are used in JavaScript as an oddity when defining a regex from a string rather than using the /literal/ notation. Both methods achieve the same result.

There are numerous resources available for learning regex patterns, and http://regex101.com is an excellent platform for testing and experimenting with different patterns.

var input = "[4]Motherboard, [25]RAM";
var pattern = '\\[(\\d+?)\\](.+)';
var result = input.split(',').map(function (item) {
  var matches = item.match(new RegExp(pattern));
  return {id: matches[1], val: matches[2]};
});

console.log(result)

Answer 4

Here's a simple way to accomplish this task using the pattern \[(\d+?)\](.+):

The (…) is a capture group, indicating that whatever matches within the brackets will be saved as a token.
\d represents a single digit.
\d+ means one or more digits in a row.
\d+? signifies one or more digits, but matching the fewest possible before moving on.
.+ matches any character at least once.

In regular expressions, [ and ] have special meanings, so if you want to include them literally, you must escape them like so: \[ and \].

The double backslashes \\ are used in JavaScript as an oddity when defining a regex from a string rather than using the /literal/ notation. Both methods achieve the same result.

There are numerous resources available for learning regex patterns, and http://regex101.com is an excellent platform for testing and experimenting with different patterns.

var input = "[4]Motherboard, [25]RAM";
var pattern = '\\[(\\d+?)\\](.+)';
var result = input.split(',').map(function (item) {
  var matches = item.match(new RegExp(pattern));
  return {id: matches[1], val: matches[2]};
});

console.log(result)

Answer 5

Answer №3

function convertStringToArray(input) {
    return {
        elements: input.split(",").map(function(item) {
            item = item.trim();
            return {
                identifier: item.substring(1, item.indexOf("]")),
                value: item.substring(item.indexOf("]") + 1),
            };
        }),
    };
}

Answer 6

function convertStringToArray(input) {
    return {
        elements: input.split(",").map(function(item) {
            item = item.trim();
            return {
                identifier: item.substring(1, item.indexOf("]")),
                value: item.substring(item.indexOf("]") + 1),
            };
        }),
    };
}

Decode the string containing indices inside square brackets and transform it into a JSON array

Answer №1

Answer №2

Answer №3

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