Deciphering the difference between a null object and the numeral 0

While working on Codewars and attempting to solve a problem, I encountered an interesting question.

The task was to create a "toDense()" function that takes a sparse array as input and returns the corresponding dense array. An example test case provided was:

var sparse = [undefined, 2, null, , , 0, 6, null];
Test.assertSimilar( toDense(sparse), [2, 0, 6]);

I wrote the following code snippet to tackle this challenge:

function toDense(sparse){
  function isBoolean(value)
  { 

    if(value >= 0)
    {
      if(!(typeof(value) === 'object'))
        return value;
    }

  }
return sparse.filter(isBoolean);

}

However, my solution did not yield the expected result of [2, 0, 6]. Instead, it only returned [2, 6]. This made me wonder why my if condition for 0 did not return its value, given that null is considered an object and 0 is a number.

Answer №1

The issue you are experiencing is due to returning 0 in the filter function, which interprets it as falsey.

const array = [0, 1, 2, 3];

console.log(array.filter(function(item) { return item; }));

Answer №2

Your analysis is hindered by erroneous conversions.

Substitute

if(value >= 0)

For

if(value > 0 || value === 0)

This rectifies your claim.

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