Create test scenarios using a two-dimensional array

I am utilizing four arrays in creating various test cases, as demonstrated below:

var phone = ['phone1', 'phone2', 'phone3']; 
var browsers = ['chrome', 'firefox']; 
var location = ['1324','2434','4234','1234','3243']; 
var network = ['3g', '4g', 'wifi']; 
var isLogin = ['service worker', 'no service worker'];

I am struggling to write code that will generate 180 different test cases. I have attempted using for loops and recursion, but haven't found the perfect solution yet. Please note that I am working with JavaScript and can only use array for loop due to certain constraints.

If anyone could provide me with some inspiration or guidance, it would be greatly appreciated!

javascriptalgorithmunit-testing

Answer №1

Exploring a scenario in Java involved using recursion, where the approach can also be applied to Javascript. The implementation entails working with 3 arrays, utilizing recursion for 2 of them.

public class Test3 {

    static String[] names = { "Ram", "Shyam", "Mohan", "Rohan", "Saket" };
    static String[] citys = { "Bhopal", "Indore", "Ujjan", "Dewas", "Rewa" };
    static String[] addresses = { "add1", "add2", "add3", "add4", "add5" };
    static StringBuffer buffer = new StringBuffer();

    public static void main(String... strings) {

        for (String name : names) {
            System.out.println(generateData(name)+"\n");
            buffer.setLength(0);
        }
    }

    public static String generateData(String name) {

        return createCombinations(name, 0, -1);
    }

    public static String createCombinations(String combination, int countA, int countB) {

        if ((countA == names.length - 1) && (countB == names.length - 1)) {

            return buffer.toString();

        }

        if (countB == addresses.length - 1) {
            countA++;
            countB = -1;
        }

        countB++;

        buffer.append(combination + citys[countA] + addresses[countB] + "\n");

        return createCombinations(combination, countA, countB);

    }

}

This solution aims to provide assistance!

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