Create a JavaScript function that accepts a number as input and generates an array containing that number repeated multiple times

Question

Create a JavaScript function that accepts a number as input and generates an array containing that number repeated multiple times

I'm new to programming and math (only took Math 101 in college), so I'm finding it difficult to tackle this problem:

Develop a function that accepts a number as input and then returns an array containing that number repeated the same amount of times.

This is the code I've written up until now:

    function numReturn(x) {
         var newArray = [];
         if (typeof x === "number") {
             return newArray.push[x]* x;
         } else {
             return null;
         }
     }

My thought process behind the code is as follows:

Create a function that can take in a number, say x.
In that function, initialize an empty array to store values later.
Verify whether the value entered for x is a number using the typeof method. If it's a number, add it to the end of the empty array. Otherwise, return null.

When I test this in the Javascript console by providing a value, it returns as undefined. Can someone provide any guidance?

javascript arrays numbers push

Answer 1

Answer №1

function createArrayWithValues(i) {
    var newArray = new Array(i);
    return newArray.fill(i);
}

or simply use return new Array(i).fill(i);. Test it out:

createArrayWithValues(4)
// --> [4, 4, 4, 4]

The Array.prototype.fill() method is part of ES6 and may not be universally supported yet. Chrome and Firefox have implemented it, IE has not - but there is a polyfill available.

To check browser compatibility:

Answer 2

function createArrayWithValues(i) {
    var newArray = new Array(i);
    return newArray.fill(i);
}

or simply use return new Array(i).fill(i);. Test it out:

createArrayWithValues(4)
// --> [4, 4, 4, 4]

The Array.prototype.fill() method is part of ES6 and may not be universally supported yet. Chrome and Firefox have implemented it, IE has not - but there is a polyfill available.

To check browser compatibility:

Answer 3

Answer №2

When you need to repeat a task multiple times, the best way to achieve this is by using a loop. There are various types of loops available, but the for loop is often the most convenient choice.

The structure of a for loop looks like this:

for(var i = 0; i < x; i++) {
    // ^initializer
    //         ^condition
    //                ^increment
    //body
}

As the loop begins, the initializer is the first step carried out. In this scenario, it initializes a variable called i with a value of 0. Next, the condition x is evaluated. If the condition i < x remains true, the loop proceeds to execute the designated body. After executing the body, the increment operation is performed (in this case,

i++</code), and then the condition is checked again. As long as the condition holds true, the loop continues to run in sequence.</p>

<p>You can implement this concept into your code like so:</p>

<pre><code>function numberLoop(x) {
    var resultArray = [];
    if (typeof x === "number") {
        for(var i = 0; i < x; i++) {
            resultArray.push(x);
        }
        return resultArray;
    } else {
        return null;
    }
}

Answer 4

When you need to repeat a task multiple times, the best way to achieve this is by using a loop. There are various types of loops available, but the for loop is often the most convenient choice.

The structure of a for loop looks like this:

for(var i = 0; i < x; i++) {
    // ^initializer
    //         ^condition
    //                ^increment
    //body
}

As the loop begins, the initializer is the first step carried out. In this scenario, it initializes a variable called i with a value of 0. Next, the condition x is evaluated. If the condition i < x remains true, the loop proceeds to execute the designated body. After executing the body, the increment operation is performed (in this case,

i++</code), and then the condition is checked again. As long as the condition holds true, the loop continues to run in sequence.</p>

<p>You can implement this concept into your code like so:</p>

<pre><code>function numberLoop(x) {
    var resultArray = [];
    if (typeof x === "number") {
        for(var i = 0; i < x; i++) {
            resultArray.push(x);
        }
        return resultArray;
    } else {
        return null;
    }
}

Answer 5

Answer №3

The code snippet newArray.push[x]* x does not actually push x times. The * operator only performs multiplication on numbers. If you want to push x times, you should use a for loop like this:

for (var i = 0; i < x; i++ )
      newArray.push(x);

After that, make sure to return the newArray.

Answer 6

The code snippet newArray.push[x]* x does not actually push x times. The * operator only performs multiplication on numbers. If you want to push x times, you should use a for loop like this:

for (var i = 0; i < x; i++ )
      newArray.push(x);

After that, make sure to return the newArray.

Answer 7

Answer №4

Referencing an answer found in the discussion on the most efficient method for creating a JavaScript array filled with zeros

function numReturn(x){
    return Array.apply(null, Array(x)).map(Number.prototype.valueOf,x);
}
console.log(numReturn(10)); // [10, 10, 10, 10, 10, 10, 10, 10, 10, 10]

Answer 8

Referencing an answer found in the discussion on the most efficient method for creating a JavaScript array filled with zeros

function numReturn(x){
    return Array.apply(null, Array(x)).map(Number.prototype.valueOf,x);
}
console.log(numReturn(10)); // [10, 10, 10, 10, 10, 10, 10, 10, 10, 10]

Answer 9

Answer №5

let count = 10
let output = Array.apply(null, {length: count}).map(() => {
    return count;
})

// Display output example
document.write(JSON.stringify(output))

Transformed into a function:

function generateNumArray(num) {
     if (typeof num === "number") {
         return Array.apply(null, {length: num}).map(() => {
            return num;
        })
     } else {
         return null;
     }
 }

Answer 10

let count = 10
let output = Array.apply(null, {length: count}).map(() => {
    return count;
})

// Display output example
document.write(JSON.stringify(output))

Transformed into a function:

function generateNumArray(num) {
     if (typeof num === "number") {
         return Array.apply(null, {length: num}).map(() => {
            return num;
        })
     } else {
         return null;
     }
 }

Create a JavaScript function that accepts a number as input and generates an array containing that number repeated multiple times

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

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