Create a fresh array that surpasses the value of its second element

Question

Create a fresh array that surpasses the value of its second element

How can we create a new array where all values are greater than the second value in the array provided? If the input array has less than two elements, the function should return false.

For example,

findValuesGreaterThanSecond([1,3,5,7])

would result in [5, 7].

findValuesGreaterThanSecond([0, -3, 2, 5])

would give us [0, 2, 5].

findValuesGreaterThanSecond([2])

should return false.

This is the approach I attempted:

function findValuesGreaterThanSecond(arr) {
  for (let val of arr) {
    if (val > arr[1]) {
      return [val];
    } else {
        return false;
    }
  }
}

javascript arrays loops return for-of-loop

Answer 1

Answer №1

If you're looking for a short solution, give this one-liner a shot:

[3, 6, -1, 9].filter((el, ind, arr) => el > arr[1])

Within the filter function are three parameters to consider:

The current element being inspected
The index of that element within the array
The original array itself

This filter method navigates through the given array and evaluates each element against the second value of the array.

Answer 2

If you're looking for a short solution, give this one-liner a shot:

[3, 6, -1, 9].filter((el, ind, arr) => el > arr[1])

Within the filter function are three parameters to consider:

The current element being inspected
The index of that element within the array
The original array itself

This filter method navigates through the given array and evaluates each element against the second value of the array.

Answer 3

Answer №2

function findValuesGreaterThanSecondElement(array) {
  
  let result = []
  console.log(array.length)
  let secondElement = array[1]
  if(array.length < 2)
    return false
  else {
    for(let i = 0; i < array.length; i++) {
      if(array[i] != secondElement && array[i] > secondElement)
        result.push(array[i])
    }
    return result
  }
}
console.log(findValuesGreaterThanSecondElement([2]))

give this method a try

Answer 4

function findValuesGreaterThanSecondElement(array) {
  
  let result = []
  console.log(array.length)
  let secondElement = array[1]
  if(array.length < 2)
    return false
  else {
    for(let i = 0; i < array.length; i++) {
      if(array[i] != secondElement && array[i] > secondElement)
        result.push(array[i])
    }
    return result
  }
}
console.log(findValuesGreaterThanSecondElement([2]))

give this method a try

Answer 5

Answer №3

Here is a suggestion for you to try out:

function findNumbersGreaterThanSecondElement(arr) {
    if (arr.length < 2)
        return false;
    return arr.filter((num) => num > arr[1]);
}
console.log(findNumbersGreaterThanSecondElement([0, -3, 2, 5]));

Answer 6

Here is a suggestion for you to try out:

function findNumbersGreaterThanSecondElement(arr) {
    if (arr.length < 2)
        return false;
    return arr.filter((num) => num > arr[1]);
}
console.log(findNumbersGreaterThanSecondElement([0, -3, 2, 5]));

Answer 7

Answer №4

Below is a suggestion you can test out:

const greaterThanSecond = arr => {
   if (arr.length > 1){ 
      return arr.filter(e => e > arr[1])
   }
   return false
}
console.log(greaterThanSecond([1,3,5,7]))

This function first checks if the array's length is at least 2 before filtering it to keep only the numbers greater than the second element.

Answer 8

Below is a suggestion you can test out:

const greaterThanSecond = arr => {
   if (arr.length > 1){ 
      return arr.filter(e => e > arr[1])
   }
   return false
}
console.log(greaterThanSecond([1,3,5,7]))

This function first checks if the array's length is at least 2 before filtering it to keep only the numbers greater than the second element.

Answer 9

Answer №5

Before suggesting another approach, let's work on fixing your code.

function valGreaterThanSecond(arr) {
  let newArr = [];
  if (arr.length < 2) return false;
  for (let elem of arr) {
    if (elem > arr[1]) {
      newArr = [...newArr, elem]
      }
    }
  return newArr;
 };

 console.log(valGreaterThanSecond([1,3,5,7]));

Your current function has a flaw where it exits the loop and returns one element in an array as soon as it finds the number greater than the second element. Additionally, if it doesn't find such a number, it immediately returns false. In the case of [1,3,5,7], it returns false because 1 is less than 3 and the function exits at that point.

Alternative Approach using reduce

Instead of using filter like some other answers, I suggest using the reduce method for arrays.

Here is a solution utilizing the reduce function:

const greaterThanSecond = (arr) => {
    if (arr.length < 2) return false;
    const result = arr.reduce((acc, curr) => {
        if (curr > arr[1]) return [...acc, curr];
        return acc;
    }, []);
    return result;
}

console.log(greaterThanSecond([1,3,5,7]));

Answer 10

Before suggesting another approach, let's work on fixing your code.

function valGreaterThanSecond(arr) {
  let newArr = [];
  if (arr.length < 2) return false;
  for (let elem of arr) {
    if (elem > arr[1]) {
      newArr = [...newArr, elem]
      }
    }
  return newArr;
 };

 console.log(valGreaterThanSecond([1,3,5,7]));

Your current function has a flaw where it exits the loop and returns one element in an array as soon as it finds the number greater than the second element. Additionally, if it doesn't find such a number, it immediately returns false. In the case of [1,3,5,7], it returns false because 1 is less than 3 and the function exits at that point.

Alternative Approach using reduce

Instead of using filter like some other answers, I suggest using the reduce method for arrays.

Here is a solution utilizing the reduce function:

const greaterThanSecond = (arr) => {
    if (arr.length < 2) return false;
    const result = arr.reduce((acc, curr) => {
        if (curr > arr[1]) return [...acc, curr];
        return acc;
    }, []);
    return result;
}

console.log(greaterThanSecond([1,3,5,7]));

Create a fresh array that surpasses the value of its second element

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

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