How can I transform the array x=[[3,1],[2,2]] into x[3][1]=1 and x[2][2]=1? Is there a way to make this code functional for arrays such as x=[[3,1],[2,12],[3,3]]?
How can I transform the array x=[[3,1],[2,2]] into x[3][1]=1 and x[2][2]=1? Is there a way to make this code functional for arrays such as x=[[3,1],[2,12],[3,3]]?
Given that you have two variables to input: pos0, pos1
for (i in x)
if (x[i][0] == pos0 && x[i][1] == pos1) {
// Perform actions
}
This code snippet essentially verifies each index
If you haven't already, one approach is to iterate through and generate a new array. Then, set the value at the specified index.
This method involves creating a fresh array to store the final output.
var arr = [[3, 1], [2, 12], [3, 3]],
resultArr = [];
arr.forEach(function (item) {
resultArr[item[0]] = resultArr[item[0]] || [];
resultArr[item[0]][item[1]] = 1;
});
console.log(resultArr);.as-console-wrapper { max-height: 100% !important; top: 0; }Here is a suggested approach:
let array = [[5,1],[2,20],[5,4]];
let result = array.reduce((previous, current) => {
if (previous[current[0]]) {
previous[current[0]][current[1]] = 1;
} else {
previous[current[0]] = Array.from({[current[1]]: 1, length: current[1]+1});
}
return previous;
}, []);
console.log(result);let arr = [[3, 1], [2, 2]]
console.log('arr =', arr)
// Creating a sparse array
let sparseArr = []
for (let index in arr) {
// Checking and initializing the inner array
sparseArr[arr[index][0]] = sparseArr[arr[index][0]] || []
// Setting value to the sparse array
sparseArr[arr[index][0]][arr[index][1]] = 1
}
console.log('sparseArr =', sparseArr)
Output:
arr = [ [ 3, 1 ], [ 2, 2 ] ]
sparseArr = [ , , [ , , 1 ], [ , 1 ] ]
To cycle through the array and verify if there is an array corresponding to the first value, you can utilize array#reduce. If not found, initialize it with [], then assign the value to that specific index.
var x=[[3,1],[2,12],[3,3]];
var result = x.reduce((r,[a,b]) => {
r[a] = r[a] || [];
r[a][b] = 1;
return r;
},[]);
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