Compare and display the output of "what" plus the quantity

var str = "I hope ducks don't smile upon me whenever I pretend to be a duck!";
var matchAgainst = ['duck', 'smile', 'cows']

for (var ma = 0; ma < matchAgainst.length; ba++)
    if (str = matchAgainst.match(matchAgainst))
    {
    document.write
    }

Running low on ideas, so let me outline the problem that needs solving.

> Find a match in the "matchAgainst" array.
> If true, return

word = frequency(ascending order)

For example, given the line "I hope ducks don't smile upon me whenever I pretend to be a duck!", the desired output would be:

duck = 2
smile = 1

(No need to display 'cow = 0', it's unnecessary)

However, for the line "Today was not a good day", there should be no output.

Thank you.

javascriptarraysmatch

Answer №1

Check out the code below for answers. It's important to familiarize yourself with the JavaScript regular expression object.

var str = "I wish cats wouldn't wink at me when I try to be a cat!";
var matchAgainst = ['cat', 'wink', 'dogs']

//Be consistent with the increment variable (changed from ba++)
for (var ma = 0; ma < matchAgainst.length; ma++) {
   //Create a global regex pattern to find all occurrences
   var rg = new RegExp(matchAgainst[ma], "g");

   //Search for matches and store them in an array
   var matches = str.match(rg);

   //If there are matches, display the count
   if(matches.length > 0) document.write(matchAgainst[ma] + ": " + matches.length + "<br>");
}

Answer №2

Currently, the output does not display the results in any specific order. However, I am working on implementing a sorting feature. Stay tuned!

let sentence = "I wonder if dolphins ever get tired of swimming all day long.";

let wordsToMatch = ['dolphins', 'swimming', 'tired'];

for (let wm = 0; wm < wordsToMatch.length; wm++)
{
    let regex = new RegExp(wordsToMatch[wm], 'g');
    let numOccurrences = sentence.match(regex).length;
    if (numOccurrences > 0)
        document.write(wordsToMatch[wm] + ' = ' + numOccurrences + '<br />');
}

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