Given two arrays:
arr1 = ['1', 'x', '0', 'x']
arr2 = ['2', '5']
The task is to replace the 'x' values in the first array with the numbers from the second array in the same order, resulting in:
arr3 = ['1', '2', '0', '5']
I am unsure how to approach this problem. I have attempted using concat() and slice() methods without success.
Loop through arr1 using Array.map(), and maintain an external counter. Whenever the element is 'x', utilize the counter to access the value from arr2, then increment the counter:
const arr1 = ['1', 'x', '0', 'x']
const arr2 = ['2', '5']
let counter = 0;
const result = arr1.map(c => c === 'x' ? arr2[counter++] : c);
console.log(result);If you have the flexibility to modify arr2, you can employ shift to retrieve the item instead of utilizing the counter:
const arr1 = ['1', 'x', '0', 'x']
const arr2 = ['2', '5']
const result = arr1.map(c => c === 'x' ? arr2.shift() : c);
console.log(result);In order to retrieve values from both arrays based on a mapping of array 1, you can use a closure to iterate through the indexes and select the correct values.
var arr1 = ['a', 'b', 'c', 'd'],
arr2 = ['1', '2', '3'],
result = arr1.map((index => value => value === 'b' ? arr2[index++] : value)(0));
console.log(result);Here is an example of how you can achieve this:
const array1 = ['apple', 'banana', 'orange', 'kiwi'];
const array2 = ['pear', 'grape'];
for(let i = 0; i < array1.length; i++) {
if (array1[i] === "orange") {
array1[i] = array2[0];// replace
array2.shift(); // delete first element
}
}
console.log(array1);
When both arrays are consistently in the correct order, handling this is a simple task:
let newArray = firstArray.map(element => element === 'x' ? secondArray.shift() : element);
It is more efficient to use a for loop instead of map when working with larger arrays.
For example:
var arr1 = ['1', 'x', '0', 'x'];
var arr2 = ['2', '5'];
var counter = 0;
for(int i = 0; i < arr1.length; i++){
if(arr1[i] === 'x'){
arr1[i] = arr2[counter];
counter++;
}
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