As I ponder the complexity of my question, I find myself wondering how to condense an array by merging adjacent strings while keeping objects intact. For example:
array = ["I","want","to",[Obj],"come","together"]
The desired output would be:
["I want to", [Obj], "come together"];
I have a hunch that array.reduce() could be the solution, but I still need to fully grasp how that function works.
Combine strings in an array or push non-strings to a new accumulator:
const array = ["I","want","to",[{}],"come","together"]
const isString = s => typeof s === 'string'
const result = array.reduce((r, o) => {
if(isString(o) && isString(r[r.length - 1])) {
r[r.length - 1] = `${r[r.length - 1]} ${o}`
} else {
r.push(o)
}
return r
}, [])
console.log(result)Here is a snippet of code that showcases how to manipulate an array in JavaScript:
const array = ["I","want","to",{},"come","together"];
let outputArr = [];
let strArr = [];
array.forEach(elem => {
if (typeof elem === 'string') {
return strArr.push(elem);
}
outputArr.push(strArr.join(' '));
strArr = [];
outputArr.push(elem);
});
outputArr.push(strArr.join(' '));
console.log(outputArr);If you're in the mood for sticking with the good old for-loop :)
var result = [], array = ["I","want","to",{a: 1, b:2},"come","together"];
var i=0;var str = "";
for(; i< array.length; i++){
if(typeof array[i] === 'object' ){
result.push(str);
result.push(array[i]);
str="";
}else{
str = str+" "+ array[i];
}
}
if(i==array.length){
result.push(str);
}
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