Is there an efficient method for combining objects from two arrays into a new list in JavaScript?
a = [{a:1, b:2, c:3}, {d:1, e:4, f:2}]
b = [{m:1, n:2, o:4}, {r:1,s:3,u:5}, {k:1,j:4,f:8}]
z = [{a:1, b:2, c:3, m:1, n:2, o:4}, {d:1, e:4, f:2, r:1,s:3,u:5}, {k:1,j:4,f:8}]
If you have lists a and b, how can you merge the objects at each position into list z?
To combine the contents of two objects, you can do so using this method:
let obj1 = [{a:1, b:2, c:3}, {d:1, e:4, f:2}]
let obj2 = [{m:1, n:2, o:4}, {r:1,s:3,u:5}, {k:1,j:4,f:8}]
let combined = [];
obj2.forEach((item, index) => {
let mergedObj = {...item, ...obj1[index]};
combined.push(mergedObj)
})
console.log(combined);To handle arrays a and b of varying lengths, exceeding the maximum length by using Object.assign to duplicate the values could be a viable method. For a versatile solution accommodating any two arrays where one may be longer than the other, it is crucial to compare their lengths throughout the process:
x = [];
for (let j = 0; j < Math.max(a.length, b.length); ++j) {
const final = j < a.length ? a[j] : {};
Object.assign(final, j < b.length ? b[j] : {});
x.push(final);
}
Give this a shot :
const arrOne = [{a:1, b:2, c:3}, {d:1, e:4, f:2}];
const arrTwo = [{m:1, n:2, o:4}, {r:1,s:3,u:5}, {k:1,j:4,f:8}];
let mergedArr = [];
if(arrOne.length > arrTwo.length){
mergedArr= arrOne.map((element, index) => {
return {
...element,
...arrTwo[index]
}
});
}else{
mergedArr = arrTwo.map((element, index) => {
return {
...element,
...arrOne[index]
}
});
}
console.log(mergedArr);One approach is to compare the lengths of two arrays before merging them.
const firstArray = [{ a: 1, b: 2, c: 3 }, { d: 1, e: 4, f: 2 }]
const secondArray = [{ m: 1, n: 2, o: 4 }, { r: 1, s: 3, u: 5 }, { k: 1, j: 4, f: 8 }]
const mergeArrays = (array1, array2) => array1.map((item, index) => ({ ...item, ...array2[index] }))
const mergedResult = firstArray.length > secondArray.length ? mergeArrays(firstArray, secondArray) : mergeArrays(secondArray, firstArray);
console.log(mergedResult);Solution:
a and b.const a = [{ a: 1, b: 2, c: 3 }, { d: 1, e: 4, f: 2 }]
const b = [{ m: 1, n: 2, o: 4 }, { r: 1, s: 3, u: 5 }, { k: 1, j: 4, f: 8 }];
const z = Array.from({ length: Math.max(a.length, b.length) }, (_, index) => ({ ...a[index] , ...b[index] }));
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