Choosing a value from the dropdown menu will reveal a textbox, but it does not retain the value that was entered into it

Question

Choosing a value from the dropdown menu will reveal a textbox, but it does not retain the value that was entered into it

In my perspective, I have

        <div class="col-md-3 ">
            @{
                List<SelectListItem> deformitylevel = new List<SelectListItem>();
                deformitylevel.Add(new SelectListItem { Value = "hip", Text = "Hip" });
                deformitylevel.Add(new SelectListItem { Value = "knee", Text = "Knee" });
                deformitylevel.Add(new SelectListItem { Value = "ankle", Text = "Ankle" });
                deformitylevel.Add(new SelectListItem { Value = "other", Text = "Other" });
            }
                @Html.DropDownListFor(model => model.DeformityLevel, deformitylevel, "--Choose Level -", new { @class = "form-control", @onchange = "showdeformitytextbox()", id = "deformitydropdown" })
                @Html.ValidationMessageFor(model => model.DeformityLevel, "", new { @class = "text-danger" })
        </div>
        <div class="col-md-3">
            @Html.EditorFor(model => model.DeformityLevel, new { htmlattributes = new { @class = "form-control", id = "deformitytextbox" ,style= "display:none"} })
        </div>

The function that guides me is

function showdeformitytextbox() {
        if ($("#deformitydropdown option:selected").text() == 'Other') {
            $("#deformitytextbox").show();

        }
        else {
            $("#deformitytextbox").hide();
        }
    }

Upon selecting "Other" in the dropdown list, instead of saving the input value from @Html.EditorFor, it saves 'other' in the database.

I am missing something crucial, any guidance?

javascript asp.net-mvc razor

Answer 1

Answer №1

To streamline this process, it's recommended to separate the model fields for the drop-down and the text box. While the code below may work, it could create extra work if you need to go back to the page with a different value selected. However, the following code correctly submits the expected value in the text box. The key idea is to disable the drop-down as you submit.

If your form has an id of submitForm set up like this:

@using (Html.BeginForm("someActionName", "someControllerName", FormMethod.Post, new { @id="submitForm"}))

Then the code below will prevent the drop-down from submitting its value during form submission:

   $("#submitForm").submit(function () {
      if ($("#deformitydropdown option:selected").text() === "Other") {
         $("#deformitydropdown").attr("disabled", true);
      } else {
         $("#deformitydropdown").removeAttr("disabled");
      }
   });

Answer 2

To streamline this process, it's recommended to separate the model fields for the drop-down and the text box. While the code below may work, it could create extra work if you need to go back to the page with a different value selected. However, the following code correctly submits the expected value in the text box. The key idea is to disable the drop-down as you submit.

If your form has an id of submitForm set up like this:

@using (Html.BeginForm("someActionName", "someControllerName", FormMethod.Post, new { @id="submitForm"}))

Then the code below will prevent the drop-down from submitting its value during form submission:

   $("#submitForm").submit(function () {
      if ($("#deformitydropdown option:selected").text() === "Other") {
         $("#deformitydropdown").attr("disabled", true);
      } else {
         $("#deformitydropdown").removeAttr("disabled");
      }
   });

Answer 3

Answer №2

To enhance the functionality, I suggest renaming your current controls and adding a hidden form element for DeformityLevel. Then use JavaScript to update its value based on events from DropdownList and text box.

***Here is an example (jq not verified, for demonstration purposes only)

<select id="DeformityLevel_DDL">
        <option></option>
        <option></option>
        <option></option>
    </select>
    <input type="text" id="DeformityLevel_TB" />
    <input type="hidden" id="DeformityLevel" name="DeformityLevel" />
    <script>
        $(document).ready(function () {
            $('#DeformityLevel_DDL').change(function () {
                if ($(this).val() != 'other') {
                    $('#DeformityLevel').val(this.val());
                }
            });

            $('#DeformityLevel_TB').on('change', function () {
                $('#DeformityLevel').val($(this).val());
            });
        });
    </script>

Answer 4

To enhance the functionality, I suggest renaming your current controls and adding a hidden form element for DeformityLevel. Then use JavaScript to update its value based on events from DropdownList and text box.

***Here is an example (jq not verified, for demonstration purposes only)

<select id="DeformityLevel_DDL">
        <option></option>
        <option></option>
        <option></option>
    </select>
    <input type="text" id="DeformityLevel_TB" />
    <input type="hidden" id="DeformityLevel" name="DeformityLevel" />
    <script>
        $(document).ready(function () {
            $('#DeformityLevel_DDL').change(function () {
                if ($(this).val() != 'other') {
                    $('#DeformityLevel').val(this.val());
                }
            });

            $('#DeformityLevel_TB').on('change', function () {
                $('#DeformityLevel').val($(this).val());
            });
        });
    </script>

Answer 5

Answer №3

It appears that your function is specifically designed to show the input in #deformitytextbox and update the model property when the value entered changes. To ensure this functions properly, consider updating the model property when changes occur. If the form automatically submits upon selecting a change, it may be necessary to utilize preventDefault.

Answer 6

It appears that your function is specifically designed to show the input in #deformitytextbox and update the model property when the value entered changes. To ensure this functions properly, consider updating the model property when changes occur. If the form automatically submits upon selecting a change, it may be necessary to utilize preventDefault.

Answer 7

Answer №4

Don't forget to give TextBox a try, but make sure your htmlAttributes parameter is correct this time. Here's the corrected version:

<div class="col-md-3 ">
    @Html.DropDownList("DeformityLevel", deformitylevel, "--Select Level -", new { @class = "form-control", @onchange = "showdeformitytextbox()", id = "deformitydropdown" })
    @Html.ValidationMessage("DeformityLevel", "", new { @class = "text-danger" })
</div>

<div class="col-md-3">
    @Html.TextBox("DeformityLevel", null, new { @class = "form-control", id = "deformitytextbox", style = "display:none;" })
</div> 

<script>
    function showdeformitytextbox() {
        if ($("#deformitydropdown option:selected").text() == 'Other') {
            $("#deformitytextbox").show();
        } else {
            $("#deformitytextbox").hide();
        }
    }
</script>

Answer 8

Don't forget to give TextBox a try, but make sure your htmlAttributes parameter is correct this time. Here's the corrected version:

<div class="col-md-3 ">
    @Html.DropDownList("DeformityLevel", deformitylevel, "--Select Level -", new { @class = "form-control", @onchange = "showdeformitytextbox()", id = "deformitydropdown" })
    @Html.ValidationMessage("DeformityLevel", "", new { @class = "text-danger" })
</div>

<div class="col-md-3">
    @Html.TextBox("DeformityLevel", null, new { @class = "form-control", id = "deformitytextbox", style = "display:none;" })
</div> 

<script>
    function showdeformitytextbox() {
        if ($("#deformitydropdown option:selected").text() == 'Other') {
            $("#deformitytextbox").show();
        } else {
            $("#deformitytextbox").hide();
        }
    }
</script>

Choosing a value from the dropdown menu will reveal a textbox, but it does not retain the value that was entered into it

Answer №1

Answer №2

Answer №3

Answer №4

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