Checking a condition with a for loop in Javascript

Question

Checking a condition with a for loop in Javascript

I'm working on developing a function that can generate a random number between 0 and 9 that is not already included in an array.

Here is the code I have come up with so far:

 var myArr = [0,2,3,4];

  console.log("Array: " + myArr);

  function newNumber(){
     console.log("testing");

     for (var i = 0; i < 10; i++) {
       var n = myArr.includes(i)
       // I am aiming to only return 'n' if it is not already present in the array
     }
     return n;
  }

newNumber()

I am looking to return a single unique number. Can someone guide me on how I can achieve this?

Appreciate the assistance.

javascript arrays loops for-loop iteration

Answer 1

Answer №1

Do you know the answer?

const invalidValues = [5,7,8,9];

const getRandomInt = (min, max) => {
    min = Math.ceil(min);
    max = Math.floor(max);
    return Math.floor(Math.random() * (max - min + 1)) + min;
}

const getValidRandomInt = (min, max) => {
  while(true) {
    let temp = getRandomInt(min,max)
      if(!invalidValues.includes(temp)) {
        return temp;
      }
  }
}

console.log(getValidRandomInt(0,15))

Answer 2

Do you know the answer?

const invalidValues = [5,7,8,9];

const getRandomInt = (min, max) => {
    min = Math.ceil(min);
    max = Math.floor(max);
    return Math.floor(Math.random() * (max - min + 1)) + min;
}

const getValidRandomInt = (min, max) => {
  while(true) {
    let temp = getRandomInt(min,max)
      if(!invalidValues.includes(temp)) {
        return temp;
      }
  }
}

console.log(getValidRandomInt(0,15))

Answer 3

Answer №2

let myArray = [1,3,5,7];
  function findNewNumber(){
     for (let j = 0; j < 15; j++) {
       if (!myArray.includes(j)) {
            return j;
       }
     }
     // return -1 if all numbers are already in the array..
     return -1;
  }

findNewNumber();

Answer 4

let myArray = [1,3,5,7];
  function findNewNumber(){
     for (let j = 0; j < 15; j++) {
       if (!myArray.includes(j)) {
            return j;
       }
     }
     // return -1 if all numbers are already in the array..
     return -1;
  }

findNewNumber();

Answer 5

Answer №3

Utilize the power of Math.random() to generate a number within a specified range. Then, iterate through and verify if the generated number exists in the given array. If the number is not found in the array, return that number:

function generateUniqueRandom(min, max, array) {
  array = new Set(array);
  while(true){
      let value =  Math.floor(Math.random() * (max - min) + min);
      if(!array.has(value)){ return value;}
    }
}
console.log(generateUniqueRandom(0, 15, [7,8,9]));

Answer 6

Utilize the power of Math.random() to generate a number within a specified range. Then, iterate through and verify if the generated number exists in the given array. If the number is not found in the array, return that number:

function generateUniqueRandom(min, max, array) {
  array = new Set(array);
  while(true){
      let value =  Math.floor(Math.random() * (max - min) + min);
      if(!array.has(value)){ return value;}
    }
}
console.log(generateUniqueRandom(0, 15, [7,8,9]));

Answer 7

Answer №4

Solution:

To obtain a random number within a specified range, utilize the formula

Math.random() * (max - min) + min

.

For integer values, either wrap the formula with Math.floor or use a bitwise OR (|) operation for smaller numbers.

function generateRandomNumber(numArray) {
 let randomNum = () => Math.random()*9 | 0,
     num = randomNum();
 while(numArray.includes(num)) {
   num = randomNum();
 }
 return num;
}

Illustration:

var myNumArray = [0,2,3,4];

function generateRandomNumber(numArray){
   let randomNum = () => Math.random()*9 | 0,
     num = randomNum();
   while(numArray.includes(num)) {
     num = randomNum();
   }
   return num;
}

let output = generateRandomNumber(myNumArray);
console.log(output);

Answer 8

Solution:

To obtain a random number within a specified range, utilize the formula

Math.random() * (max - min) + min

.

For integer values, either wrap the formula with Math.floor or use a bitwise OR (|) operation for smaller numbers.

function generateRandomNumber(numArray) {
 let randomNum = () => Math.random()*9 | 0,
     num = randomNum();
 while(numArray.includes(num)) {
   num = randomNum();
 }
 return num;
}

Illustration:

var myNumArray = [0,2,3,4];

function generateRandomNumber(numArray){
   let randomNum = () => Math.random()*9 | 0,
     num = randomNum();
   while(numArray.includes(num)) {
     num = randomNum();
   }
   return num;
}

let output = generateRandomNumber(myNumArray);
console.log(output);

Answer 9

Answer №5

let arrayNumbers= [1,3,7];
function getRandomNumber(arrayNumbers, n){
    n ? n : 1;
    let number = Math.random() * n;
    if(arrayNumbers.indexOf( number ) !==-1 ) {
        return getRandomNumber( arrayNumbers, n );
    }
    return number;
}
getRandomNumber(arrayNumbers, 20);

Answer 10

let arrayNumbers= [1,3,7];
function getRandomNumber(arrayNumbers, n){
    n ? n : 1;
    let number = Math.random() * n;
    if(arrayNumbers.indexOf( number ) !==-1 ) {
        return getRandomNumber( arrayNumbers, n );
    }
    return number;
}
getRandomNumber(arrayNumbers, 20);

Answer 11

Answer №6

To find the first missing number in the given array, the code snippet provided above suggests looping through a range of numbers and checking if each value exists in the array. Once a value is found to be missing, it is returned as the result.

 var myArr = [0,2,3,4]; // original array

  function findMissingNumber(){

     for (var i = 0; i < 10; i++) { // loop through i from 0-9

       if (myArr.indexOf(i) === -1){ // check for the first missing number
        return i; //return it
       }
     }
  }

findMissingNumber()

Answer 12

To find the first missing number in the given array, the code snippet provided above suggests looping through a range of numbers and checking if each value exists in the array. Once a value is found to be missing, it is returned as the result.

 var myArr = [0,2,3,4]; // original array

  function findMissingNumber(){

     for (var i = 0; i < 10; i++) { // loop through i from 0-9

       if (myArr.indexOf(i) === -1){ // check for the first missing number
        return i; //return it
       }
     }
  }

findMissingNumber()

Checking a condition with a for loop in Javascript

Answer №1

Answer №2

Answer №3

Answer №4

Solution:

Illustration:

Answer №5

Answer №6

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