Is there a way in JavaScript to determine if a single Bit is On (1) or Off (0)?
function isBitOn(number, index)
{
// ... ?
}
// Example:
let num = 13; // 1101
isBitOn(num, 0); // true 1
isBitOn(num, 1); // false 0
isBitOn(num, 2); // true 1
isBitOn(num, 3); // true 1
I'm familiar with Bitwise Operations in JavaScript. How can these operations be used, or are there other methods available to check a single Bit?
Within JavaScript, the tradition of C binary operators lives on. By utilizing the "index," you can shift the value 1 to the left and then perform an AND operation with the desired number:
function checkBitStatus(num, indx) {
return Boolean(num & (1 << indx));
}
console.log(checkBitStatus(13, 0));
console.log(checkBitStatus(13, 1));
console.log(checkBitStatus(13, 2));
console.log(checkBitStatus(13, 3));
console.log(checkBitStatus(13, 4));
console.log(checkBitStatus(13, 5));
console.log(checkBitStatus(13, 6));It's important to remember that this involves the bitwise & operator, not the short-circuit logical operator &&.
Keep in mind that these operators consider the numbers as 32-bit integers, thus may not be suitable for very large numbers.
Transform the number into binary and then verify each individual bit:
function isBitOn(number, index) {
let binary = number.toString(2);
return (binary[(binary.length - 1) - index] == "1"); // check index in reverse order
}
let num = 13; // 1101
console.log(isBitOn(num, 0));
console.log(isBitOn(num, 1));
console.log(isBitOn(num, 2));
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