I've experimented with several regular expressions, including the ones below:
1> var pattern = "(.)\\1{2,}";
2> var pattern = "^(?!.*(.)\\1{2,})";
regexExp = new RegExp(pattern);
When I test them, this is the output I receive:
regexExp.test("sss is true")
regexExp.test("ss is false")
regexExp.test("sdsdsd is false") //instead of being true.
My regular expressions only consider consecutively repeated characters and not others.
You can include .* before \1 (to match any 0+ characters except line breaks) and utilize this regex pattern:
/(.)(?:.*\1){2,}/
Alternatively, if the input string may contain line breaks:
/([\s\S])(?:[\s\S]*\1){2,}/
Refer to the example of this regex. In JavaScript regex, [\s\S] (or [^]) matches any character, while . excludes line break characters.
About the Method
(.) - captures any single character(?:.*\1){2,} - signifies two or more consecutive instances of:
.* - represents any sequence of characters excluding line breaks\1 - refers back to the value captured in Group 1 (same character)Consider this example:
let phrase = "hello world";
let hasRepeatedLetters = (/([a-zA-Z]).*?\1/).test(phrase);
console.log("Phrase contains repeated letters: ", hasRepeatedLetters);
let word = 'abcdeaf';
if (word.match(/(.).*\1/) {} else {}
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