Check for Vue: see if the user is disconnected and display a div for a brief moment when they reconnect

Question

Check for Vue: see if the user is disconnected and display a div for a brief moment when they reconnect

Currently, I have implemented a function within a timed loop to monitor if a user goes offline:

created() {
   setInterval(() => {
        this.checkOnline();
   }, 30000);
}

Function:

checkOnline(){
   this.status = navigator.onLine ? true : false;
}

Is there a more efficient way to detect online status without relying on a timer?

Additionally...

I want to display a brief alert message when the user comes back online. The idea is to hide a div element when the user is online or offline. When transitioning from offline to online, briefly show the div for about one second and then hide it again. I've attempted using setTimeout and watchers but haven't achieved the desired result.

Edit:

One approach that partially addresses this issue is:

 data() {
     return {
         status: navigator.onLine ? true : false,
     }
 }

Followed by a watcher to handle the back-online notification:

watch: {
    status: function (val) {
        if(this.status === true){
            this.showAlert = true;
            setTimeout(()=>{ this.showAlert = false; }, 1000);
        }
    },
},

Are there alternative methods to achieve this functionality other than utilizing a watcher or a dedicated notify plugin?

javascript vue.js vuejs2

Answer 1

Answer №1

Is it possible to detect this without relying on a timer? Absolutely. By leveraging the online offline event.

Are there alternative methods to using a watcher or notify plugin for this task? I believe the watcher is the most effective approach in this scenario.

Example: https://jsfiddle.net/jacobgoh101/xz6e3705/4/

new Vue({
    el: "#app",
    data: {
        onLine: navigator.onLine,
        showBackOnline: false
    },
    methods: {
        updateOnlineStatus(e) {
            const {
                type
            } = e;
            this.onLine = type === 'online';
        }
    },
    watch: {
        onLine(v) {
            if (v) {
                this.showBackOnline = true;
                setTimeout(() => {
                    this.showBackOnline = false;
                }, 1000);
            }
        }
    },
    mounted() {
        window.addEventListener('online', this.updateOnlineStatus);
        window.addEventListener('offline', this.updateOnlineStatus);
    },
    beforeDestroy() {
        window.removeEventListener('online', this.updateOnlineStatus);
        window.removeEventListener('offline', this.updateOnlineStatus);
    }
})

Answer 2

Is it possible to detect this without relying on a timer? Absolutely. By leveraging the online offline event.

Are there alternative methods to using a watcher or notify plugin for this task? I believe the watcher is the most effective approach in this scenario.

Example: https://jsfiddle.net/jacobgoh101/xz6e3705/4/

new Vue({
    el: "#app",
    data: {
        onLine: navigator.onLine,
        showBackOnline: false
    },
    methods: {
        updateOnlineStatus(e) {
            const {
                type
            } = e;
            this.onLine = type === 'online';
        }
    },
    watch: {
        onLine(v) {
            if (v) {
                this.showBackOnline = true;
                setTimeout(() => {
                    this.showBackOnline = false;
                }, 1000);
            }
        }
    },
    mounted() {
        window.addEventListener('online', this.updateOnlineStatus);
        window.addEventListener('offline', this.updateOnlineStatus);
    },
    beforeDestroy() {
        window.removeEventListener('online', this.updateOnlineStatus);
        window.removeEventListener('offline', this.updateOnlineStatus);
    }
})

Answer 3

Answer №2

To update the online status, you can simply use arrow functions in event listeners to set a variable to true or false based on the event. There is no need to constantly check for the navigator.online value or use interval timers. By setting up event listeners for the online and offline events provided by the window object, you can easily handle changes in connectivity. In the code snippet below, I have initialized an 'isOnline' variable based on the initial navigator.online value. Using event listeners for online and offline events, the variable is updated accordingly. This variable is then used in the template to display a message to the user using the v-if directive.

data() {
  return {
    isOnline: navigator.online
  }
},
mounted() {
  window.addEventListener('online', () => { this.isOnline = true });
  window.addEventListener('offline', () => { this.isOnline = false });
},

Answer 4

To update the online status, you can simply use arrow functions in event listeners to set a variable to true or false based on the event. There is no need to constantly check for the navigator.online value or use interval timers. By setting up event listeners for the online and offline events provided by the window object, you can easily handle changes in connectivity. In the code snippet below, I have initialized an 'isOnline' variable based on the initial navigator.online value. Using event listeners for online and offline events, the variable is updated accordingly. This variable is then used in the template to display a message to the user using the v-if directive.

data() {
  return {
    isOnline: navigator.online
  }
},
mounted() {
  window.addEventListener('online', () => { this.isOnline = true });
  window.addEventListener('offline', () => { this.isOnline = false });
},

Check for Vue: see if the user is disconnected and display a div for a brief moment when they reconnect

Answer №1

Answer №2

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