Changing the array of objects: various operations on arrays and objects

Question

Changing the array of objects: various operations on arrays and objects

Array of Data

[
 {group: 'a', tab: "1", name: 'input1'},
 {group: 'b', tab: "1", name: 'input2'},
 {group: 'b', tab: "1", name: 'input3'},
 {group: 'c', tab: "2", name: 'input4'},
 {group: 'a', tab: "1", name: 'input5'},
 {group: 'c', tab: "2", name: 'input6'},
];

In my application, each element in the array (totaling over 50) represents an input that is part of a specific group (a, b, or c) and tab (1, 2, etc.). To achieve my goal, I aim to determine how many groups are associated with each tab by creating an object or array with this structure:

 [
      {tab1:{groups: ["a", "b"]}},
      {tab2:{groups: ["c"]}},
    ]

javascript arrays object

Answer 1

Answer №1

To create a distinct array and manipulate each item, we can utilize the Set method for uniqueness, map function to modify items, and filter to eliminate elements from the array. Here is how I achieved it:

Generate a unique tab list.
Transform the list to generate a new object for each tab
1. Apply filter to identify tabs of a specific type
2. Map that filtered result to extract only the group letter
3. Create another set for a unique group letter list.
Finally, the revised object is fed back to the initial map item to produce an array of items.

This implementation appears as shown below:

let data = [
 {group: 'a', tab: "1", name: 'input1'},
 {group: 'b', tab: "1", name: 'input2'},
 {group: 'b', tab: "1", name: 'input3'},
 {group: 'c', tab: "2", name: 'input4'},
 {group: 'a', tab: "1", name: 'input5'},
 {group: 'c', tab: "2", name: 'input6'},
];

let tabs = [...new Set(data.map(itm => itm.tab))].map(tab => {
  return {
    ['tab' + tab]: {groups: [...new Set(data.filter(i => i.tab == tab).map(i => i.group))] }
  }
});

console.log(tabs);

Answer 2

To create a distinct array and manipulate each item, we can utilize the Set method for uniqueness, map function to modify items, and filter to eliminate elements from the array. Here is how I achieved it:

Generate a unique tab list.
Transform the list to generate a new object for each tab
1. Apply filter to identify tabs of a specific type
2. Map that filtered result to extract only the group letter
3. Create another set for a unique group letter list.
Finally, the revised object is fed back to the initial map item to produce an array of items.

This implementation appears as shown below:

let data = [
 {group: 'a', tab: "1", name: 'input1'},
 {group: 'b', tab: "1", name: 'input2'},
 {group: 'b', tab: "1", name: 'input3'},
 {group: 'c', tab: "2", name: 'input4'},
 {group: 'a', tab: "1", name: 'input5'},
 {group: 'c', tab: "2", name: 'input6'},
];

let tabs = [...new Set(data.map(itm => itm.tab))].map(tab => {
  return {
    ['tab' + tab]: {groups: [...new Set(data.filter(i => i.tab == tab).map(i => i.group))] }
  }
});

console.log(tabs);

Answer 3

Answer №2

Utilize the power of Array.reduce() to efficiently create a map and group it based on Tab values, then extract the desired result using Object.values().

let arr = [
    {group: "a", tab: "1", name: "input1"},
    {group: "b", tab: "1", name: "input2"},
    {group: "b", tab: "1", name: "input3"},
    {group: "c", tab: "2", name: "input4"},
    {group: "a", tab: "1", name: "input5"},
    {group: "c", tab: "2", name: "input6"}
];

let result = Object.values(arr.reduce((a, {group, tab})=>{
  a[tab] = a[tab] || {["tab"+tab] : {group : []}};
  if(!a[tab]["tab"+tab].group.includes(group))
    a[tab]["tab"+tab].group.push(group);
  return a;
},{}));

console.log(result);

:

Answer 4

Utilize the power of Array.reduce() to efficiently create a map and group it based on Tab values, then extract the desired result using Object.values().

let arr = [
    {group: "a", tab: "1", name: "input1"},
    {group: "b", tab: "1", name: "input2"},
    {group: "b", tab: "1", name: "input3"},
    {group: "c", tab: "2", name: "input4"},
    {group: "a", tab: "1", name: "input5"},
    {group: "c", tab: "2", name: "input6"}
];

let result = Object.values(arr.reduce((a, {group, tab})=>{
  a[tab] = a[tab] || {["tab"+tab] : {group : []}};
  if(!a[tab]["tab"+tab].group.includes(group))
    a[tab]["tab"+tab].group.push(group);
  return a;
},{}));

console.log(result);

:

Answer 5

Answer №3

One effective approach is to utilize a Map for grouping and a Set for storing unique values.

const data = [{ group: 'a', tab: '1', name: 'input1' }, { group: 'b', tab: '1', name: 'input2' }, { group: 'b', tab: '1', name: 'input3' }, { group: 'c', tab: '2', name: 'input4' }, { group: 'a', tab: '1', name: 'input5' }, { group: 'c', tab: '2', name: 'input6' }];
const result = Array.from(
    data.reduce(
        (m, { tab, group }) => m.set(tab, (m.get(tab) || new Set).add(group)),
        new Map
    ),
    ([tab, groups]) => ({ ['tab' + tab]: { groups: Array.from(groups) } })
);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 6

One effective approach is to utilize a Map for grouping and a Set for storing unique values.

const data = [{ group: 'a', tab: '1', name: 'input1' }, { group: 'b', tab: '1', name: 'input2' }, { group: 'b', tab: '1', name: 'input3' }, { group: 'c', tab: '2', name: 'input4' }, { group: 'a', tab: '1', name: 'input5' }, { group: 'c', tab: '2', name: 'input6' }];
const result = Array.from(
    data.reduce(
        (m, { tab, group }) => m.set(tab, (m.get(tab) || new Set).add(group)),
        new Map
    ),
    ([tab, groups]) => ({ ['tab' + tab]: { groups: Array.from(groups) } })
);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 7

Answer №4

Give this code a try

const data = [
  { group: "x", tab: "1", name: "item1" },
  { group: "y", tab: "1", name: "item2" },
  { group: "y", tab: "1", name: "item3" },
  { group: "z", tab: "2", name: "item4" },
  { group: "x", tab: "1", name: "item5" },
  { group: "z", tab: "2", name: "item6" },
];

const modify = (data) => {
  const result = [];
  Object.keys(data).forEach((element) => {
    const ref = `tab${data[element].tab}`;
    
    if (typeof (result[ref]) === 'undefined') {
      result[ref] = { groups: [] };
    }
  
    if (!result[ref].groups.includes(data[element].group)) {
      result[ref].groups.push(data[element].group);
    }
  });
  return result;
};

console.log(modify(data));

Answer 8

Give this code a try

const data = [
  { group: "x", tab: "1", name: "item1" },
  { group: "y", tab: "1", name: "item2" },
  { group: "y", tab: "1", name: "item3" },
  { group: "z", tab: "2", name: "item4" },
  { group: "x", tab: "1", name: "item5" },
  { group: "z", tab: "2", name: "item6" },
];

const modify = (data) => {
  const result = [];
  Object.keys(data).forEach((element) => {
    const ref = `tab${data[element].tab}`;
    
    if (typeof (result[ref]) === 'undefined') {
      result[ref] = { groups: [] };
    }
  
    if (!result[ref].groups.includes(data[element].group)) {
      result[ref].groups.push(data[element].group);
    }
  });
  return result;
};

console.log(modify(data));

Changing the array of objects: various operations on arrays and objects

Answer №1

Answer №2

Answer №3

Answer №4

Similar questions

Add some flair to your list by animating the text within it

What is the process for associating JSON reponses with button actions on a webpage?

Saving an Axios request array to a Laravel controller in Laravel using VueJs

Ways to display a variable prior to making an axios request

loop failing to refresh element within array

Is dividing a website into two parts acceptable?

Integrating Dart with external libraries

Tips for transferring complete HTML content within a JSON payload

Troubleshooting: WordPress failing to launch Bootstrap Modal

Exploring AngularJS unit testing: integrating async and await with Jasmine

Are your divs getting truncated?

Why does the address bar show value changes in IE when using window.location.hash, but the value doesn't change in the DOM when going

The Vue.js development server compiler is hitting a roadblock at 49% progress

The Angular controller failed to return a defined value

Material-UI is having trouble resolving the module '@material-ui/core/styles/createMuiTheme'

Encountering difficulties accessing functions from apollo-server-express

Utilize Vue to call a method by providing its name as a string

Updating an object with AngularJS

Calculating the total length of an SVG element using React

Remove all $.ajax requests from content that has been loaded using $.ajax in jQuery