Changing a MySQL "where" clause into a Sequelizejs "where" clause

Struggling to translate the query "WHERE (CASE ... THEN ... ELSE ... END) > 0" into sequelize v3.33.

Tried using sequelize.literal('...') without success. Although using "HAVING" is a potential solution, it's not ideal for performance with large datasets, as it can be twice as slow.

This snippet depicts MySQL code that closely resembles my objective.

SELECT
(CASE `a`.`fee` IS NULL 
  THEN `a.b`.`fee` 
  ELSE `a`.`fee`
END) AS `_fee`
FROM `a`
WHERE
(CASE `a`.`fee` IS NULL 
  THEN `a.b`.`fee` 
  ELSE `a`.`fee`
END) > 0 AND 
(created_at > currentDate 
  AND 
created_at < futureDate)

I am aiming to convert this into sequelize. The provided code showcases my progress so far, but I'm stuck on how to implement the case statement.

models.a.findAll({
  ...
  where: {
    created_at: { $gt: startDate, $lt: endDate }
  }
})

*** Please disregard the reference to created_at, as it is meant purely as an example.

Answer №1

To achieve this, you can make use of sequelize.where and sequelize.literal:

where:{
    $and : [
        { created_at: { $gt: startDate, $lt: endDate } },
        sequelize.where(sequelize.literal('(CASE `a`.`fee` IS NULL THEN `a.b`.`fee` ELSE `a`.`fee` END)') , { $gt : 0 } )
    ]
} 

Keep in mind that using alias a may not always work as expected. Make sure to debug and adjust it according to your specific query requirements.

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