Change ES6 JavaScript to ES5 standard

Question

Change ES6 JavaScript to ES5 standard

Is there a way to transform this code snippet from other questions into ES5 format?

I am attempting to extract data from a JSON array.

var match = function(query, input) {
  return input.filter(function(entry) {
    return Object.entries(query).every(function(pair) {
      var k = pair[0];
      var v = pair[1];
      return entry[k] === v;
    });
  });
};

javascript json

Answer 1

Answer №1

To easily convert ES6 code to ES5, use Babel

https://babeljs.io/

Easily set up a build process to develop in ES6 and then transpile your code to ES5 for compatibility with older browsers.

Answer 2

To easily convert ES6 code to ES5, use Babel

https://babeljs.io/

Easily set up a build process to develop in ES6 and then transpile your code to ES5 for compatibility with older browsers.

Answer 3

Answer №2

Let's break this down step by step and start by making the formatting a bit more ES5-friendly:

const match = (query, input) => {
  return input.filter((entry) => {
    return Object.entries(query).every(([k, v]) => {
      return entry[k] === v;
    });
  });
};

To eliminate ES6-specific syntax, we can rewrite it as follows:

function match(query, input) {
  return input.filter(function(entry) {
    return Object.entries(query).every(function(kv) {
      return entry[kv.k] === kv.v;
    });
  });
}

Lastly, let's remove the Object.entries() method call:

function match(query, input) {
  return input.filter(function(entry) {
    return Object.keys(query).every(function(key) {
      return entry[key] === query[key];
    });
  });
}

Answer 4

Let's break this down step by step and start by making the formatting a bit more ES5-friendly:

const match = (query, input) => {
  return input.filter((entry) => {
    return Object.entries(query).every(([k, v]) => {
      return entry[k] === v;
    });
  });
};

To eliminate ES6-specific syntax, we can rewrite it as follows:

function match(query, input) {
  return input.filter(function(entry) {
    return Object.entries(query).every(function(kv) {
      return entry[kv.k] === kv.v;
    });
  });
}

Lastly, let's remove the Object.entries() method call:

function match(query, input) {
  return input.filter(function(entry) {
    return Object.keys(query).every(function(key) {
      return entry[key] === query[key];
    });
  });
}

Answer 5

Answer №3

const findMatch = function search(query, items) {
  return items.filter(function (item) {
    return Object.keys(query).every(function (keyValuePair) {
      var key = keyValuePair[0],
          value = keyValuePair[1];
      return item[key] === value;
    });
  });
};

Answer 6

const findMatch = function search(query, items) {
  return items.filter(function (item) {
    return Object.keys(query).every(function (keyValuePair) {
      var key = keyValuePair[0],
          value = keyValuePair[1];
      return item[key] === value;
    });
  });
};

Change ES6 JavaScript to ES5 standard

Answer №1

Answer №2

Answer №3

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