Challenge of loops: decreasing a variable

I've been trying to figure out the proper way to achieve this task. Although I did find a solution, I'm not entirely sure if it's the correct approach.

The requirement is to utilize a for loop to decrement the variable countDown by one each time the loop runs until it reaches 0.

var countDown = 10; 

for (let i=0; i < 5; i++)
countDown = countDown-i

console.log(countDown) // outputs 0;

While my method does work, it doesn't precisely decrement by one. Another alternative approach that crossed my mind was:

var countDown = 10;

for(i=0; i < 11; i++){
console.log(countDown-i);
}

console.log(countDown) // outputs 10, 9 , 8, 7, 6, 5, 4, 3, 2, 1, 0, 10

I'm now contemplating how I could globally change the countDown variable to 0?

Answer №1

let counter = 10;
for(let j = 0; j < 10; j++){
  counter--;
}

console.log(counter); //display 0;

Answer №2

Easily achieve this using a simple for loop method.

    var countdown = 10;
    for(;countdown > 0; countdown--) { 
        console.log(countdown);
    }
    console.log(countdown);

Depending on the specific scenario, you can also place the var within the for loop like so

for(var countdown = 10; countdown > 0; countdown--)

Answer №3

To create a countdown in your loop, simply set the variable to decrement while it is greater than -1.

for (var countDown = 10; countDown > 0; countDown--)
{
  console.log(countDown);
}
console.log(countDown);

Answer №4

let countDown = 10;
// ADD CODE HERE

for (let decrease=10; decrease <=10 && decrease > 0;)
{
    decrease--
}

// Uncomment the below line to check your work 
//console.log(decrease) // -> should print 0;

This code will decrement the countDown by 1 from 10 to 0, but only the zero should be displayed after running.

The output will be 0 once the code is executed.

If you want to display the countDown from 10 to 0, modify the for loop as follows:

for (let count=10; count <=10 && count > 0; count--);

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