Capitalizing a specific letter in a string at a designated index

Looking for an efficient way to convert a specific letter in a string to uppercase? Let's explore different methods:

Suppose we have the string:

let str = "Dwightschrute";

One way to achieve this is by slicing the string and then updating the desired index:

let str = "Dwightschrute";

let a = str.slice(0, 6);
console.log(a); // Dwight

let b = (str.slice(6, 7)).toUpperCase();
console.log(b); // S

let c = str.slice(7);

console.log(c);

console.log(a + b + c); // DwightSchrute

Alternatively, you can convert the string into an array, update the desired element, and join it back into a string:

let str = "Dwightschrute";

str = [...str];

str[6] = str[6].toUpperCase();

console.log(str.join('')); // DwightSchrute

Although these methods work, they may seem complex. Are there other simpler ways to accomplish the same task? Feel free to explore and share!

Answer №1

I personally lean towards the initial version, but without the extra variables in between. Instead of using the .slice function call, you can opt for bracket notation to extract just one character – it gives a cleaner look:

const str = "Dwightschrute";
const result = str.slice(0, 6) + str[6].toUpperCase() + str.slice(7);
console.log(result); //DwightSchrute

Alternatively, another approach is to employ a regular expression that targets the character following the first 6 characters. You can then integrate a replacer function to invoke toUpperCase on that specific character. Whether this method seems more appealing or not is entirely subjective:

const str = "Dwightschrute";
const result = str.replace(/(?<=.{6})./, char => char.toUpperCase());
console.log(result); //DwightSchrute

Here's another option without utilizing lookbehind:

const str = "Dwightschrute";
const result = str.replace(/(.{6})(.)/, (_, initial, char) => initial + char.toUpperCase());
console.log(result); //DwightSchrute

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