Can you organize an array based on groups of n elements and the number of decreasing integers within each group (n-1)? The goal is to determine the total number of resulting arrays

Question

Can you organize an array based on groups of n elements and the number of decreasing integers within each group (n-1)? The goal is to determine the total number of resulting arrays

Consider the input array: [2, 1, 4, 4, 3]

In this array, a total of n-1 patterns can be identified from left to right.

The resulting output will be the number 7 since the arrays are grouped as follows:

[2] [1] [4] [4] [3] - 1 group (n)

[4, 3] - 1 group (n-1)

[2, 1] - 1 group (n-1)

Output: 7 (arrays)

This snippet provides an initial attempt where everything is simply summed up together.

let numbers = [2, 1, 4, 4, 3];
let sum = numbers.reduce(function (previousValue, currentValue) {
    return previousValue + currentValue;
});

console.log(sum);

I would appreciate guidance on how to properly solve this problem in JavaScript. Thanks!

javascript arrays sorting output group

Answer 1

Answer №1

Code Sample:

function findUniqueAndRelated() {
  let numbers = [2, 1, 4, 4, 3];
  // Remove duplicates
  let unique = [...new Set(numbers)];
  // Calculate the length of the unique array and add it to the length of filtered unique array containing n-1
  console.log(unique.length + unique.filter(number => numbers.includes(number - 1)).length);
}

Find the number of unique elements and add it to the count of filtered unique elements that also contain n-1.

Result:

https://i.sstatic.net/kCmmr.png

If you want to retrieve the arrays:

function findUniqueAndRelated() {
  let numbers = [2, 1, 4, 4, 3];
  let unique = [...new Set(numbers)];
  var arrays = [];
  unique.forEach(number => {
    arrays.push([number]); 
    if(numbers.includes(number - 1))
      arrays.push([number, number-1])
  });

  console.log(arrays.length)
  console.log(arrays)
}

https://i.sstatic.net/GGGrp.png

Answer 2

Code Sample:

function findUniqueAndRelated() {
  let numbers = [2, 1, 4, 4, 3];
  // Remove duplicates
  let unique = [...new Set(numbers)];
  // Calculate the length of the unique array and add it to the length of filtered unique array containing n-1
  console.log(unique.length + unique.filter(number => numbers.includes(number - 1)).length);
}

Find the number of unique elements and add it to the count of filtered unique elements that also contain n-1.

Result:

https://i.sstatic.net/kCmmr.png

If you want to retrieve the arrays:

function findUniqueAndRelated() {
  let numbers = [2, 1, 4, 4, 3];
  let unique = [...new Set(numbers)];
  var arrays = [];
  unique.forEach(number => {
    arrays.push([number]); 
    if(numbers.includes(number - 1))
      arrays.push([number, number-1])
  });

  console.log(arrays.length)
  console.log(arrays)
}

https://i.sstatic.net/GGGrp.png

Can you organize an array based on groups of n elements and the number of decreasing integers within each group (n-1)? The goal is to determine the total number of resulting arrays

Answer №1

Code Sample:

Result:

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