Can you explain the logic behind the continuation of the "if" condition even when it returns false? What causes it to persist despite being untrue

Specific conditions were established where a number should be greater than those surrounding it, but unfortunately the condition did not hold true.

for (var i = 0; i + 1 < n; i++) {
    if (arr[i] < arr[i + 1] || arr[i + 1] > arr[i + 2]) {
        count++;
        index1 = i + 1;
    }
}

The array values are as follows: arr=[1, 2, 3, 6, 5, 4, 7, 8], with n being equal to 8.

In this case, the count will increase when arr[i+1] is smaller than arr[i+2].

Answer №1

It is advisable to use the AND condition instead of OR when checking if a value is greater than both the left and right values.

See the example code snippet below:

var arr=[1, 2, 3, 6, 5, 4, 9, 8];
var n=8;
var count = 0;
var pos = [];
for (var i = 0; i + 1 < n; i++) {
    if (arr[i] < arr[i + 1] && arr[i + 1] > arr[i + 2]) {
        count++;
        index1 = i + 1;
        pos.push(index1);
    }
}
console.log("positions: "+pos);
console.log("count: "+count);

Answer №2

The issue lies within the logical operator || (OR) because

when true || false is used, the result will always be true 

On the other hand, using && (AND) will yield

if true && false is implemented, the outcome will be false

To resolve this problem, adjust your function to utilize "&&" instead of "||"

let array =[1, 2, 3, 6, 5, 4, 9, 8];
let num = 8;
let counter = 0;
for (let index = 0; index + 1 < num; index++) {
    if (array[index] < array[index + 1] && array[index + 1] > array[index + 2]) {
        counter++;
        pointer = index + 1;
    }
}

For more information, please visit https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Logical_Operators

Answer №3

As the value of i approaches 6, there is an attempt to access array[i+2] where i+2 equals 8. This results in an out-of-bounds error since the array only has 8 elements indexed from 0 to 7. In JavaScript, accessing a value outside of an array returns undefined, which is considered a falsy value (interpreted as false).

To learn more about falsy values, visit:

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