Can you determine the top-rated product category by comparing the arrays provided in JavaScript?

Question

Can you determine the top-rated product category by comparing the arrays provided in JavaScript?

Here are two arrays to consider:

const items = [
  {
    name: 'item1',
    type: 'Fruit'
  },
  {
    name: 'item2',
    type: 'Vegetable'
  },
  {
    name: 'item3',
    type: 'Snack'
  }];


const prices = [
  {
    name: 'item1',
    price: 5,
  },
  {
    name: 'item2',
    price: 8
  },
  {
    name: 'item3',
    price: 10,
  }];

If we want to determine the category with the highest total price, how can this be achieved? For instance, item1 and item2 fall under the same category 'Produce' so the total for Produce would be 5 + 8 = 13.

One approach could involve creating a modified array of items where each element includes the corresponding price from the second array. From there, iterating through the adjusted array to generate a final array consisting of objects containing category and totalPrice might be considered.

In this process, if the final array already contains a category object, updating the total by adding the new price value is necessary; otherwise, inserting a new entry with category: totalPrice will suffice.

Is it possible to optimize this procedure further?

javascript arrays sorting

Answer 1

Answer №1

It is common knowledge that canonical grouping follows this pattern...

const prodsByCategory = products.reduce((acc, p) => {
  let cat = p.category;
  if (!acc[cat]) acc[cat] = [];
  acc[cat].push(p);
  return acc;
}, {});

To enhance optimization, we can make some modifications to the existing code.

const prodsByCategory = products.reduce((acc, p) => {
  let cat = p.category;
  // maintaining an array and total instead of just an array
  if (!acc[cat]) acc[cat] = { products: [], totalRate: 0 };
  // push product and add rate to the total
  acc[cat].products.push(p);
  acc[cat].totalRate += rateForProduct(p) || 0;
  return acc;
}, {});

We will also need a function called rateForProduct for the rate lookup:

const rateForProduct = product => {
  return rate.find(r => r.name === product.name)?.rate || 0;
}

The result should be an object categorized by category with each value containing a totalRate property. Sort these entries to maximize the first one. Here's an example...

const products = [{
    name: 'prod1',
    category: 'Meat'
  },
  {
    name: 'prod2',
    category: 'Meat'
  },
  {
    name: 'prod3',
    category: 'Dairy'
  }
];

const rate = [{
    name: 'prod1',
    rate: 23,
  },
  {
    name: 'prod2',
    rate: 36
  },
  {
    name: 'prod3',
    rate: 50,
  }
];

const rateForProduct = product => {
  return rate.find(r => r.name === product.name)?.rate || 0;
}

const prodsByCategory = products.reduce((acc, p) => {
  let cat = p.category;
  if (!acc[cat]) acc[cat] = {
    products: [],
    totalRate: 0
  };
  acc[cat].products.push(p);
  acc[cat].totalRate += rateForProduct(p);
  return acc;
});

const sortedEntries = Object.entries(prodsByCategory).sort((a, b) => b[1].totalRate - a[1].totalRate);

const bestEntry = {
  category: sortedEntries[0][0],
  rate: sortedEntries[0][1].totalRate
}
console.log(bestEntry);

Answer 2

It is common knowledge that canonical grouping follows this pattern...

const prodsByCategory = products.reduce((acc, p) => {
  let cat = p.category;
  if (!acc[cat]) acc[cat] = [];
  acc[cat].push(p);
  return acc;
}, {});

To enhance optimization, we can make some modifications to the existing code.

const prodsByCategory = products.reduce((acc, p) => {
  let cat = p.category;
  // maintaining an array and total instead of just an array
  if (!acc[cat]) acc[cat] = { products: [], totalRate: 0 };
  // push product and add rate to the total
  acc[cat].products.push(p);
  acc[cat].totalRate += rateForProduct(p) || 0;
  return acc;
}, {});

We will also need a function called rateForProduct for the rate lookup:

const rateForProduct = product => {
  return rate.find(r => r.name === product.name)?.rate || 0;
}

The result should be an object categorized by category with each value containing a totalRate property. Sort these entries to maximize the first one. Here's an example...

const products = [{
    name: 'prod1',
    category: 'Meat'
  },
  {
    name: 'prod2',
    category: 'Meat'
  },
  {
    name: 'prod3',
    category: 'Dairy'
  }
];

const rate = [{
    name: 'prod1',
    rate: 23,
  },
  {
    name: 'prod2',
    rate: 36
  },
  {
    name: 'prod3',
    rate: 50,
  }
];

const rateForProduct = product => {
  return rate.find(r => r.name === product.name)?.rate || 0;
}

const prodsByCategory = products.reduce((acc, p) => {
  let cat = p.category;
  if (!acc[cat]) acc[cat] = {
    products: [],
    totalRate: 0
  };
  acc[cat].products.push(p);
  acc[cat].totalRate += rateForProduct(p);
  return acc;
});

const sortedEntries = Object.entries(prodsByCategory).sort((a, b) => b[1].totalRate - a[1].totalRate);

const bestEntry = {
  category: sortedEntries[0][0],
  rate: sortedEntries[0][1].totalRate
}
console.log(bestEntry);

Can you determine the top-rated product category by comparing the arrays provided in JavaScript?

Answer №1

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