Imagine a scenario where the following code snippet exists:
function write3(a, b, c) {
document.write(a + " " + b + " " + c);
}
var arr = [1, 2, 3];
var i = 0;
write3(arr[i++], arr[i++], arr[i++]);The expected outcome is 1 2 3 when running this code. However, questions remain about the guaranteed behavior. Is it possible for the arguments passed to the function write3 to be resolved in an order other than left to right?
Absolutely, the sequence in which arguments are evaluated follows a left-to-right approach.
As outlined in sections 12.4.3 and 12.4.4 of the ES6 specification, function arguments adhere to the concept of Argument Lists and are consistently processed from left to right.
In simpler terms, the function being called is assessed first, followed by the evaluation of its arguments arranged from left to right.
Is it possible for the arguments supplied to
write3to be resolved in any order besides left to right?
No, the resolution of arguments will always occur from left to right. This behavior is guaranteed.
It's worth mentioning that you can invoke a function with an array of arguments using apply:
write3.apply(null, arr)
. . . or utilize the spread operator in ES6+ (may not be universally supported across browsers):
write3(...arr)
function write3(a, b, c) {
document.write(a + " " + b + " " + c)
}
var arr = [1, 2, 3]
write3.apply(null, arr)
write3(...arr)Subsequently. When utilizing ES6, you have the option to express it as:
display3(...numArr)
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