App.js
Updated
import x from 'project/a'
Is it possible to change it to:
var project = 'a'
if(project == 'a')
{
import x from 'project/a'
}
else
{
import x from 'project/b'
}
or would this alternative method work:
var project = 'a'
var filepath = '';
if(project == 'a')
{
filepath = 'project/a';
}
else
{
filepath = 'project/b';
}
import x from filepath
There are two ways to approach this:
Combine the code for projectA and projectB into one file with a conditional statement.
import initProjectA
import initProjectB
if (condition) {
initProjectA()
} else {
initProjectB()
}
When compiled, it will look like this:
function initProjectA() {
}
function initProjectB() {
}
if (condition) {
//
}
With dynamic imports, three separate files will be created: projectA, projectB, and conditional.
import(module).then(importedModule => {
importedModule.default() // assuming you did `export default`
})
The conditional file will only load and execute one of them based on the condition.
To use dynamic imports, you may need to adjust some configurations. Search for "webpack dynamic imports" for more information.
If you want to conditionally import a file in JavaScript, you can follow this approach:
var project = 'a'
let x;
if(project == 'a')
{
x = require('project/a').default;
}
else
{
x = require('project/b').default;
}
Make sure you are using export default in the files you are importing.
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