Take a look at this code snippet:
const myFunction = (x, y, z) => {
//Some code here
};
$('whatever').on( event, function(){
myFunction( event.originalEvent && event.originalEvent.target ); //What is this operator doing?
});
Can you explain the purpose of the operator used in the function parameter?
The && operator will return the first non-truthy expression or the last evaluated expression if both are truthy.
In essence, by checking if e.originalEvent exists, you ensure that if it does, the value of e.originalEvent.target will be passed as the first parameter to func. If e.originalEvent doesn't exist, it will be undefined, and in that scenario, undefined will be passed to
a</code, skipping the evaluation of <code>e.originalEvent.targetTake into account the following examples:
console.log(1 && 2);
# 2
console.log(null && 2);
# null
console.log(undefined && 2);
# undefined
console.log(0 && 2);
# 0
Keep in mind: Only one argument is being passed, so by default, b and c will be undefined.
This expression is quite straightforward. The function will process the two values by using the AND operator.
For example, if e.originalEvent has a value that is not null, false, or undefined, it will return e.originalEvent.target.
Next, we have the variable
x.originalEvent && x.originalEvent.targetd, e, and f resulting in undefined.
If d && e is true, it will return d, otherwise it will return e.
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