Can an inline try be implemented without including a catch block as demonstrated?

Question

Can an inline try be implemented without including a catch block as demonstrated?

I have a scenario where I need to execute code that may result in an error without catching it.

If the response is not valid JSON, then the desired outcome should be 0:

Here is the code snippet I am considering:

var overallProgress = try {JSON.parse(text)} ? 0;

Is there a way to achieve this?

Alternatively, could something like this work:

var overallProgress = try { JSON.parse(text)} catch(error) { 0 }; 
var overallProgress = try { JSON.parse(text)} catch(error) { overallProgress = 0 };

However, errors are encountered when using the above code.

I came across a similar post below but did not find any solution:

Is try {} without catch {} possible in JavaScript?

To make it easier on the eyes:

var overallProgress = 0; 
try { overallProgress = JSON.parse(text).overallProgress } 
catch(error) { overallProgress = 0 };

javascript try-catch

Answer 1

Answer №1

Indirectly, yes. One method is utilizing an IIFE:

const overallProgress = (() => { try { return JSON.parse(text) } catch { return 0 } })();

However, it is recommended to structure it over multiple lines for better readability:

const overallProgress = (() => {
  try {
    return JSON.parse(text);
  } catch {
    return 0;
  }
})();

While using const has its perks, there isn't a significant advantage compared to using separate assignments like this:

let overallProgress;
try {
  overallProgress = JSON.parse(text);
} catch {
  overallProgress = 0;
}

Alternatively, you could start with a default value and then attempt to update it through parsing:

let overallProgress = 0;
try {
  overallProgress = JSON.parse(text);
} catch {
  /* ignore: maintain the current `overallProgress` value */
}

Answer 2

Indirectly, yes. One method is utilizing an IIFE:

const overallProgress = (() => { try { return JSON.parse(text) } catch { return 0 } })();

However, it is recommended to structure it over multiple lines for better readability:

const overallProgress = (() => {
  try {
    return JSON.parse(text);
  } catch {
    return 0;
  }
})();

While using const has its perks, there isn't a significant advantage compared to using separate assignments like this:

let overallProgress;
try {
  overallProgress = JSON.parse(text);
} catch {
  overallProgress = 0;
}

Alternatively, you could start with a default value and then attempt to update it through parsing:

let overallProgress = 0;
try {
  overallProgress = JSON.parse(text);
} catch {
  /* ignore: maintain the current `overallProgress` value */
}

Can an inline try be implemented without including a catch block as demonstrated?

Answer №1

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