I am looking to organize multiple sets of information, each containing specific details. This is how I envision it:
var users = [{userID:1, userName:robert}, {userID:2, userName:daniel}]
Then, when I want to access this data:
users.userID // 1, 2
users.userName // robert, daniel
I want to easily retrieve information based on the userID associated with it.
When considering your issue, I would suggest restructuring the array in the following way:
var usersList = { 'id1' : { 'name' :'Robert'},
'id2': { 'name': 'Daniel'}};
alert(usersList.id1.name);
alert(eval('usersList.id' + 1 + '.name'));
In case you need some assistance, here is a sample code snippet:
let targetID = 2;
let users = [ {id: 1, name: "Alice"}, {id: 2, name: "Bob"} ];
for (let i = 0; i <= users.length; i++) {
if (users[i].id === targetID) {
alert(users[i].name);
}
}
Here is a code snippet that creates an array of user IDs:
[{userID:1, userName:robert},
{userID:2, userName:daniel}].map(function (x) { return x.userID; });Absolutely, there are several ways to achieve this. Let's say you have:
var users = [{userID: 1, userName: robert}, {userID: 2, userName: daniel}];
To get the userID and userName for Robert, you can access them using users[0].userID and users[0].userName.
If you prefer to access them using users.userID[0] and users.userName[0], you should structure it like this:
var users = {userID: [1, 2], userName: [robert, daniel]};
If you're wondering how to convert the first format to the second one, you can use this function:
function transform(source) {
var result = {};
for (var i = 0; i < source.length; i++) {
for (property in source[i]) {
if (typeof result[property] == "undefined")
result[property] = [];
result[property].push(source[i][property]);
}
}
}
Apply it like so:
var transformed_users = transform(users);
Keep in mind that this transformation function is tailored to your specific data structure.
Check out this method for achieving the desired outcome
let nums1 = new Array(5,6,7,8);
let nums2 = new Array(12,13,14,15,16,17);
let nums3 = new Array( nums1, nums2);
console.log(nums1);
console.log(nums2);
console.log(nums3);
This approach will yield the correct outcomes
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