This is the code I have implemented:
return s => counts.get(s) || 0;
// Sample callIn this function, my goal is to take in two arrays as input and output a single array when calling the function.
For example:
f(a,b)=array where a and b are two arrays combined into one
To optimize the counts, you can create a mapping of the given values and then adjust any undefined values in the process.
function updateValues(values, counts) {
return values
.map(
Map.prototype.get,
counts.reduce((map, s) => map.set(s, (map.get(s) || 0) + 1), new Map)
)
.map(v => v || 0);
}
console.log(updateValues(["wer", "tyu", "uio"], ["wer", "wer", "tyu", "oio", "tyu"]));If you want to merge two arrays into one, you can do so using the built-in Array.prototype.concat method.
function mergeArrays (arr1, arr2) {
return arr1.concat(arr2);
}
const arrayOne = [1,2,3];
const arrayTwo = [4,5,6];
console.log(mergeArrays(arrayOne, arrayTwo));However, it seems like your code example doesn't match exactly what you're trying to achieve. Are you looking to sum up all elements from both arrays into a single value?
function sumOfArrays(arr1, arr2) {
return arr1.concat(arr2).reduce((acc, curr) => acc + curr);
}
const arrayOne = [1,2,3];
const arrayTwo = [4,5,6];
console.log(sumOfArrays(arrayOne, arrayTwo));More about Array.concat() Method Learn how to use Array.reduce() Method
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