Can an array be generated on-the-fly with objects contained within it?

Question

Can an array be generated on-the-fly with objects contained within it?

Seeking advice on looping through an array of objects to achieve a specific result.

Here is the initial array:

var testArray = [{'name':'name1', 'xaxis':'xaxis1', 'yaxis':'yaxis1'}, 
                 {'name':'name2', 'xaxis':'xaxis2', 'yaxis':'yaxis2'}];

The length of the array may vary, but the keys remain consistent.

The desired result should be:

var resultArray = [
                   trace1 = {title: 'name1', x: 'xaxis1', y: 'yaxis1'},
                   trace2 = {title: 'name2', x: 'xaxis2', y: 'yaxis2'},
                   ];

Started by creating variable names for JSON objects like this:

for (var i = 0; i < testArray.length; ++i) {
    resultArray[i] = 'trace' + i;
}

Struggling with how to proceed in generating the JSON objects. Any advice would be appreciated.

javascript arrays json loops object

Answer 1

Answer №1

Your solution using a loop to create trace objects based on testArray elements is quite clever.

However, the issue with trace1 = being incorrect JSON is something that needs to be addressed.

To fix this, you can modify the loop to construct an array of trace objects instead:
var testArray = [{'name':'name1', 'xaxis':'xaxis1', 'yaxis':'yaxis1'}, 
                 {'name':'name2', 'xaxis':'xaxis2', 'yaxis':'yaxis2'}];

var resultArray = [];
                   
for (var i = 0; i < testArray.length; ++i) {
    resultArray.push({ name: 'trace' + (i+1), title: testArray[i].name, x: testArray[i].xaxis, y: testArray[i].yaxis });
}

Answer 2

Your solution using a loop to create trace objects based on testArray elements is quite clever.

However, the issue with trace1 = being incorrect JSON is something that needs to be addressed.

To fix this, you can modify the loop to construct an array of trace objects instead:
var testArray = [{'name':'name1', 'xaxis':'xaxis1', 'yaxis':'yaxis1'}, 
                 {'name':'name2', 'xaxis':'xaxis2', 'yaxis':'yaxis2'}];

var resultArray = [];
                   
for (var i = 0; i < testArray.length; ++i) {
    resultArray.push({ name: 'trace' + (i+1), title: testArray[i].name, x: testArray[i].xaxis, y: testArray[i].yaxis });
}

Answer 3

Answer №2

To simplify the declaration of an Array of objects, you can use the map helper function as shown below.

let id=0;
const coordinatesArray = [
  {
    'name': 'name1',
    'xaxis': 'xaxis1',
    'yaxis': 'yaxis1'
  },
  {
    'name': 'name2',
    'xaxis': 'xaxis2',
    'yaxis': 'yaxis2'
  }
].map(item => ({
  [`trace${++id}`]: {
    title: item.name,
    x: item.xaxis,
    y: item.yaxis
  }
}))

console.log(resultArray)

Answer 4

To simplify the declaration of an Array of objects, you can use the map helper function as shown below.

let id=0;
const coordinatesArray = [
  {
    'name': 'name1',
    'xaxis': 'xaxis1',
    'yaxis': 'yaxis1'
  },
  {
    'name': 'name2',
    'xaxis': 'xaxis2',
    'yaxis': 'yaxis2'
  }
].map(item => ({
  [`trace${++id}`]: {
    title: item.name,
    x: item.xaxis,
    y: item.yaxis
  }
}))

console.log(resultArray)

Answer 5

Answer №3

To implement this functionality, you can utilize the .map() method:

const sampleData = [{
    'type': 'type1',
    'value1': 'val1',
    'value2': 'val2'
  },
  {
    'type': 'type2',
    'value1': 'val3',
    'value2': 'val4'
  }
];

const newDataArray = sampleData.map((item, index) => ({
  [`data${index + 1}`]: {
    type: item.type,
    val1: item.value1,
    val2: item.value2
  }
}))

console.log(newDataArray)

Answer 6

To implement this functionality, you can utilize the .map() method:

const sampleData = [{
    'type': 'type1',
    'value1': 'val1',
    'value2': 'val2'
  },
  {
    'type': 'type2',
    'value1': 'val3',
    'value2': 'val4'
  }
];

const newDataArray = sampleData.map((item, index) => ({
  [`data${index + 1}`]: {
    type: item.type,
    val1: item.value1,
    val2: item.value2
  }
}))

console.log(newDataArray)

Can an array be generated on-the-fly with objects contained within it?

Answer №1

Answer №2

Answer №3

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