Can a variable be initialized with a concealed or additional argument?

After just 2 weeks of coding, I'm struggling to find information on how to initialize a variable with an extra argument in a recursive function call. Is this even possible? And if it is, are there any scenarios where it's considered best practice?


This question arose while I was working on a less-than-elegant solution to CoderByte challenge number 10 (Alphabet Soup - a challenge that involves taking a string and returning a string with the same letters in alphabetical order). [Note: I understand that my approach may not be the best way to solve the problem. I'm including the code only for context.]

In essence, I'm wondering if there's a way to remove 'newStr' as an argument (given that JavaScript functions can take extra arguments) and still pass a recursively growing answer string. If I simply eliminate 'newStr' as an argument, the initialization is lost. However, if I initialize 'newString' within the function body (var newStr = ""), I encounter issues passing the sorted string recursively. Is there a valid use case for this approach, or does it simply signify that another method should be used?

Full Code:

function AlphabetSoup(str, newStr) { 
  var alphabet = "abcdefghijklmnopqrstuvwxyz";
  var testVal= 0;
  //ATTEMPTING TO PASS A GROWING ANSWER STRING RECURSIVELY
  if (newStr == null)
    var newStr = "";
  if (str.length == 0)
    return newStr;
  for (var i = 1; i < str.length; i++) {
    if (alphabet.indexOf(str[0]) <= alphabet.indexOf(str[i])) {
      testVal += 1;
    }
  }
  // When the first letter, str[0], is earlier in the alphabet than every other letter
  if (testVal == (str.length - 1)) {
    //add the first letter to the newStr
    newStr = newStr + str[0];
    //remove the first letter from the input string
    str = str.substr(1);
    //recursively call AlphabetSoup to continue building newStr
    return AlphabetSoup(str, newStr);
  }
  //When the first letter isn't the earliest in the alphabet
  else {
    //move it to the end of str
    str = str.substr(1) + str[0];
    //until we find the next earliest letter in the alphabet
    return AlphabetSoup(str, newStr);
  }
}

console.log(AlphabetSoup("hooplah"));

Answer №1

Sure, you could theoretically inspect the length of the arguments object and assign your variable based on a specific index, like arguments[1], in relation to your comment about "JavaScript functions accepting additional arguments." However, this approach may seem somewhat unsophisticated. It's perfectly fine to include that argument as part of the function signature. If you prefer not to expose it externally, consider encapsulating your recursive logic within a wrapper function with just one parameter.

Answer №2

The concept of checking newStr at the beginning is a common practice in JavaScript. However, it's important to check for undefined rather than null:

if (typeof newStr == "undefined") {
    var newStr = "";
}

In ES6 (or Coffeescript), you can set default values for your function arguments:

function AlphabetSoup(str, newStr = '') {
    // ...
}

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