Callback for Vue asynchronous components

Question

Callback for Vue asynchronous components

<template>
    <div>
        <DynamicComponentA></DynamicComponentA>
        <!-- Display DynamicComponentB only after DynamicComponentA is loaded -->
        <DynamicComponentB></DynamicComponentB>
    </div>
</template>

<script>
export default {
    name: "Example Component"
    components: {
        DynamicComponentA: () => import("./DynamicComponentA"),
        DynamicComponentB: () => import("./DynamicComponentB")
    }
};
</script>

I'm trying to asynchronously load two components within a single component, but I need one of them to render only after the other has finished loading. Do you think that's achievable?

javascript asynchronous vue.js vuejs2

Answer 1

Answer №1

To implement a conditional rendering based on a reference within another component, use the v-if directive.

<template>
   <div>
       <AsyncComponent1 ref="component1"></AsyncComponent1>
       <!-- Show AsyncComponent2 only if AsyncComponent1 is rendered -->
       <AsyncComponent2 v-if="$refs.component1"></AsyncComponent2>
   </div>
</template>

Answer 2

To implement a conditional rendering based on a reference within another component, use the v-if directive.

<template>
   <div>
       <AsyncComponent1 ref="component1"></AsyncComponent1>
       <!-- Show AsyncComponent2 only if AsyncComponent1 is rendered -->
       <AsyncComponent2 v-if="$refs.component1"></AsyncComponent2>
   </div>
</template>

Answer 3

Answer №2

To achieve this functionality, you can set up the first component to trigger an event that is caught by its parent component and used to control the visibility of the second component.

<template>
    <div>
        <AsyncComponent1 v-on:completedLoading="componentLoaded"></AsyncComponent1>
        <!-- Show AsyncComponent2 only after AsyncComponent1 has loaded -->
        <AsyncComponent2 v-if="hasLoadedComponent"></AsyncComponent2>
    </div>
</template>

<script>
export default {
    name: "ParentComponent",
    components: {
        AsyncComponent1: () => import("./AsyncComponent1"),
        AsyncComponent2: () => import("./AsyncComponent2")
    },
    data() {
        return {
            hasLoadedComponent: false
        }
    },
    methods: {
        componentLoaded() {
            this.hasLoadedComponent = true;
        }
    }
};
</script>

Inside AsyncComponent1.vue:


...
mounted() {
    this.$emit("completedLoading");
}
...

Answer 4

To achieve this functionality, you can set up the first component to trigger an event that is caught by its parent component and used to control the visibility of the second component.

<template>
    <div>
        <AsyncComponent1 v-on:completedLoading="componentLoaded"></AsyncComponent1>
        <!-- Show AsyncComponent2 only after AsyncComponent1 has loaded -->
        <AsyncComponent2 v-if="hasLoadedComponent"></AsyncComponent2>
    </div>
</template>

<script>
export default {
    name: "ParentComponent",
    components: {
        AsyncComponent1: () => import("./AsyncComponent1"),
        AsyncComponent2: () => import("./AsyncComponent2")
    },
    data() {
        return {
            hasLoadedComponent: false
        }
    },
    methods: {
        componentLoaded() {
            this.hasLoadedComponent = true;
        }
    }
};
</script>

Inside AsyncComponent1.vue:


...
mounted() {
    this.$emit("completedLoading");
}
...

Callback for Vue asynchronous components

Answer №1

Answer №2

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