let array1 = [2,4,6]
let array2 = [3,3,3]
let result = dotProduct(array1,array2) // should return 36
Can you suggest a streamlined approach to creating the dotProduct function without relying on external libraries?
let array1 = [2,4,6]
let array2 = [3,3,3]
let result = dotProduct(array1,array2) // should return 36
Can you suggest a streamlined approach to creating the dotProduct function without relying on external libraries?
dotProduct = (vector1, vector2) => vector1.map((element, index) => vector1[index] * vector2[index]).reduce((accumulator, currentValue) => accumulator + currentValue);
console.log(dotProduct([1,2,3], [1,0,1]));In this code snippet, we are utilizing Array.prototype.map to generate a new array with multiplied values at each index and Array.prototype.reduce to calculate the sum of the resulting array.
Analysis of Performance (median time in milliseconds based on a thousand runs):
let methods=[
// (0.65) similar to kyun's solution but without extra variable
'v.reduce((l,r,i)=>l+r*w[i],0)',
// (0.66) akin to kyun's approach
'v.reduce((l,r,i)=>{l+=(r*w[i]);return l},0)',
// (0.71) utilizing external length declaration
'let s2=0,l2=v.length;for(let i2=0;i2<l2;i2++)s2+=v[i2]*w[i2]',
// (0.72) block-scoped length variable
'let s=0;for(let i=0,l=v.length;i<l;i++)s+=v[i]*w[i]',
// (1.20) resembling the accepted solution
'v.map((_,i)=>v[i]*w[i]).reduce((l,r)=>l+r)',
// (1.93) hardcoding length value
'let s1=0;for(let i1=0;i1<1e4;i1++)s1+=v[i1]*w[i1]',
// (2.05) verifying length in each iteration
'let s3=0;for(let i3=0;i3<v.length;i3++)s3+=v[i3]*w[i3]',
// (6.25) omitting `let` for sum variable
's4=0;for(let i4=0,l4=v.length;i4<l4;i4++)s4+=v[i4]*w[i4]',
// (12.17) absent use of `let`
's5=0;l5=v.length;for(i5=0;i5<l5;i5++)s5+=v[i5]*w[i5]',
// (16.36) employing `var` instead of `let`
'var s6=0,l6=v.length;for(var i6=0;i6<l6;i6++)s6+=v[i6]*w[i6]'
]
methods.sort(()=>Math.random()-.5)
let v=Array.from({length:1e4},()=>Math.random())
let w=Array.from({length:1e4},()=>Math.random())
for(let method of methods){
let startTime=process.hrtime.bigint()
eval(method)
let endTime=process.hrtime.bigint()
console.log(endTime-startTime+'\t'+method)
}
To mitigate optimization impacts from running identical code repeatedly, I executed the benchmark as
for i in {0..999};do node script.js;doneLooking for a straightforward solution to this issue? Check out this method!
function calculateProduct(array1, array2) {
let product = 0;
for (let index = 0; index < array1.length; index++) {
product += array1[index] * array2[index];
}
return product;
}
console.log(calculateProduct([1, 2, 3], [4, 5, 6])) // output: 32let x = [4,6,8]
let y = [3,0,2]
let z = dotProduct(x,y) // equals 32
console.log(z);
function dotProduct(x,y){
let result = x.reduce((sum, current, index)=>{
sum += (current * y[index]);
return sum;
}, 0);
return result;
}Consider attempting this:
calculate.dotProduct(a, b)
For more information, refer to the documentation here:
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