I'm currently working on finding an elegant solution to a toy example pattern. The goal is to stop the reduce algorithm immediately and return 0 when an element with a value of 0 is encountered, without processing the rest of the elements.
let factors = [2,3,6,0,9,4,4,4];
function product(arr) {
return arr.reduce((acc, elem) => (acc * elem), 1);
}
Is there a way to exit the reduce iteration early?
To streamline the reduction process, you have the option to alter the original array directly.
let factors = [2, 3, 6, 0, 9, 4, 4, 4];
function calculateProduct(arr) {
return arr.reduce((acc, elem, i, array) => (array[i] === 0 ? (arr.length = i, elem) : (acc * elem)), 1);
}
console.log(calculateProduct(factors))checkout this code snippet - https://jsfiddle.net/johndoe1994/xtu09zz9/ Let me explain the functionality of the code The code contains two containers: .first and .second. The .first container has two default divs with a class of .item. The .second contai ...
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