Building a properly formatted JSON object using JavaScript

Question

Building a properly formatted JSON object using JavaScript

I have been using the following code to build a JSON object with specific data:

{"contacts":[{"provider":"Yahoo","firstName":"myname","lastName":"surname","nickname":"mynick","email":"example@example.com","photoURL":"http://l.yimg.com/dh/ap/social/profile/profile_bxx.png"}]};

var data = {};
var contacts;
var gc = $.when(gigya.socialize.getContacts({callback: function(response){
  data['contacts'] = response.contacts.asArray();
}}));
gc.done(function(response) {
  contacts = data;
});
console.log(contacts);

However, when I try to pass this contacts object to a Google soy template, there seems to be an issue with the structure of the JSON object.

Can someone provide guidance on how to properly construct a valid JSON object using the code above?

Thank you for your assistance.

javascript json google-closure

Answer 1

Answer №1

The item appears to be in good condition.

Consider using the JOSN.stringify() function, as shown in this jsFiddle example
or utilizing JSON.parse()

As demonstrated in the example, you can convert an object into valid JSON and then reverse it back into a valid JavaScript object.

In reference to your code:

What information are you receiving from response?
Also, why are you including response here if you are not using it?
```
gc.done(function(response) {
  contacts = data;
});
```

I suggest updating this line EDITED:

data['contacts'] = response.contacts.asArray();

to

contacts = JSON.parse(response.contacts);

and removing:

gc.done(function(response) {
  contacts = data;
});

Answer 2

The item appears to be in good condition.

Consider using the JOSN.stringify() function, as shown in this jsFiddle example
or utilizing JSON.parse()

As demonstrated in the example, you can convert an object into valid JSON and then reverse it back into a valid JavaScript object.

In reference to your code:

What information are you receiving from response?
Also, why are you including response here if you are not using it?
```
gc.done(function(response) {
  contacts = data;
});
```

I suggest updating this line EDITED:

data['contacts'] = response.contacts.asArray();

to

contacts = JSON.parse(response.contacts);

and removing:

gc.done(function(response) {
  contacts = data;
});

Building a properly formatted JSON object using JavaScript

Answer №1

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