I am struggling to understand the execution flow of this return statement. If someone could clarify how it works and perhaps discuss the advantages and disadvantages of using such a complex statement instead of a more readable multi-line statement, I would greatly appreciate it.
return option = option ? option : {}, typeof option.xValue == "boolean" && (_ready = option.xValue), option.name && _ready == false && log(option.name + "(" + option.caller + " ) API not ready.", "E"), _ready
This specific expression utilizes the comma operator to execute multiple statements, along with the short-circuit functionality of the && operator in the form of an if condition.
The code can be represented as follows:
if (!option) {
option = {};
}
if (typeof option.xValue == "boolean") {
_ready = option.xValue;
}
if (option.name && _ready == false) {
log(option.name + "(" + option.caller + " ) API not ready.", "E")
}
return _ready;
The primary benefit of consolidating the statements into a single complex expression is its conciseness. This may be done to obfuscate the code or simply to reduce its length.
Refer to the operator precedence table to determine the grouping of operators in the expression:
return
option =
option ? option : {},
typeof option.xValue == "boolean" &&
(_ready = option.xValue),
option.name &&
_ready == !1 &&
log(option.name + "(" + option.caller + " ) API not ready.", "E"),
_ready
The comma operator used to separate parameters evaluates each expression and returns the result of the rightmost one. It first assigns the value to option, then evaluates the && expressions which may affect _ready or call log(), and ultimately returns the value of _ready.
The parentheses around the _ready assignment seem unnecessary, possibly added for clarity.
Writing such a complex statement may not serve a practical purpose, often done to showcase one's cleverness. Check out Guffa's answer for a simplified version of the code.
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