Avoid turning negative numbers into NaN by ensuring that you do not divide by zero

Question

Avoid turning negative numbers into NaN by ensuring that you do not divide by zero

When attempting to convert NaN to false, negative numbers are also affected.

-0.2|0     //this operation will always result in zero when the number is negative

I wanted to perform a bitwise operation quickly and inline, minimizing the number of steps, as I am simultaneously storing the result in an array.

array[i]=(sum)|0

Sometimes, my sum value may lead to NaN.

To clarify my question and address the core issue... why is -0.2 considered false when -1 is not? -0.2 is not equal to zero! Zero is false, but -0.2 is a negative value where -0.2!==0.

javascript nan

Answer 1

Answer №1

In order to properly assign sum to a Number (not an integer as indicated by |), you should first cast it. If sum returns NaN, you can assign zero by using the following code:

array[i]= (+sum) || 0;

Answer 2

In order to properly assign sum to a Number (not an integer as indicated by |), you should first cast it. If sum returns NaN, you can assign zero by using the following code:

array[i]= (+sum) || 0;

Answer 3

Answer №2

Why prioritize making code as short as possible just for the purpose of inlining it in an expression? Quality code doesn't necessarily mean short code.

With that in mind, you might want to consider this alternative approach:

function handleNaN( value ) {
    return isNaN( value ) ? 0 : value;
}

// implementation
array[index] = handleNaN( total );

Answer 4

Why prioritize making code as short as possible just for the purpose of inlining it in an expression? Quality code doesn't necessarily mean short code.

With that in mind, you might want to consider this alternative approach:

function handleNaN( value ) {
    return isNaN( value ) ? 0 : value;
}

// implementation
array[index] = handleNaN( total );

Avoid turning negative numbers into NaN by ensuring that you do not divide by zero

Answer №1

Answer №2

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