Automatically formatting text upon entering it in Vue.js

I need assistance with auto-formatting the postal code entered by the user. The rule for the postal code is to use the format A0A 0A0 or 12345. If the user inputs a code like L9V0C7, it should automatically reformat to L9V 0C7. However, if the postal code consists only of digits, such as 12345, it should remain unchanged. The maximum length should be 6 characters when the code includes both numbers and letters, and 5 characters when it contains only numbers. Can you help me troubleshoot this handlePostalCode method?

The problem I am encountering is that when I input L9V0, the '0' disappears and I am unable to continue entering the postal code.

<v-text-field
    label='Postal Code'
    class="required"
    v-model='postal_code'
    required
    @input="handlePostalCode"
    validate-on-blur
    :rules='postalCodeRules'>
</v-text-field>

postalCodeRules: [
  value => /^[A-z]\d[A-z] \d[A-z]\d$|^\d\d\d\d\d$/.test(value) || 'Please use the format A0A 0A0 or 12345'
  ]


handlePostalCode() {
 if (this.postal_code.match(/^[0-9]+$/) != null) {
      var replacedInput = this.postal_code.replace(/\D/g, '').match(/(\d{0,3})(\d{0,2})/);
      this.postal_code = !replacedInput[2] ? replacedInput[1] : replacedInput[1] + '' + replacedInput[2];
 }
 else {
      var replacedInput = this.postal_code.match(/(\w{0,3})(\w{0,3})/);
      console.log(replacedInput)
      this.postal_code = !replacedInput[2] ? replacedInput[1] : replacedInput[1] + ' ' + replacedInput[2];
 }
}

Answer №1

One issue arises when a space is entered after the initial three characters of A0A. The regular expression (\w{0,3})(\w{0,3}) fails to span across that space, resulting in an empty string match for the second capture group and losing any subsequent characters.

To address this problem, consider the following suggestions:

  • Differentiate between the first and second postal code rules based on the first character alone: apply the first rule if it is a digit, otherwise apply the second rule

  • Simplify the logic for handling an all-numbers scenario: once non-digit characters are removed, limit the string length to 5 using the slice method

  • For the second rule, start by eliminating all non-alphanumeric characters (including spaces)

  • Subsequently, remove any digit immediately following another digit, as well as any letter immediately following another letter

  • Lastly, trim the string to 6 characters and insert a space if there are at least 4 characters present

Below is an updated version of your function:

function _handlePostalCode() {
    this.postal_code = /^\d/.test(this.postal_code)
        ? this.postal_code.replace(/[^\d]/g, "")
                          .slice(0, 5)
        : this.postal_code.replace(/\W/g, "")
                          .replace(/(\d)(?:\d+)|([A-Z])(?:[A-Z]+)/gi, "$1$2")
                          .slice(0, 6)
                          .replace(/^(...)(.)/, "$1 $2");
}

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