Below is a breakdown of the array structure:
[{
name: "Mobile Uploads"
}, {
name: "Profile Pictures"
}, {
name: "Reports"
}, {
name: "Instagram Photos"
}, {
name: "Facebook"
}, {
name: "My Account"
}, {
name: "Twitter"
}]
The goal is to rearrange the array so that it starts with Profile Pictures, followed by Mobile Uploads, Instagram Photos, and then the remaining objects sorted in alphabetical order.
To achieve the desired outcome, create an object specifically designed to handle sorting exceptions. Afterwards, develop a custom sort() function that takes into consideration these exceptions.
var list = [{
name: "Date"
}, {
name: "Mobile Uploads"
}, {
name: "Profile Pictures"
}, {
name: "Fig"
}, {
name: "Instagram Photos"
}, {
name: "Cherry"
}, {
name: "Apple"
}, {
name: "Banana"
}];
var exceptions = {
"Profile Pictures": 1,
"Mobile Uploads": 2,
"Instagram Photos": 3
}
list.sort(function(a, b) {
if (exceptions[a.name] && exceptions[b.name]) {
// Handle cases where both items are exceptions
return exceptions[a.name] - exceptions[b.name];
} else if (exceptions[a.name]) {
// If only `a` is in exceptions, move it to the front of the list
return -1;
} else if (exceptions[b.name]) {
// If only `b` is in exceptions, move it to the back of the list
return 1;
} else {
// No exceptions found, perform a standard alphabetical sort
return a.name.localeCompare(b.name);
}
});
console.log(list); var sortingAlgorithm = [{
name: "Mobile Uploads"
},
{
name: "Zeta"
},
{
name: "Beta"
},
{
name: "Alfa"
},
{
name: "Profile Pictures"
},
{
name: "Instagram Photos"
}]
var compareFunction = function(a,b){
var weightTable = {"Profile Pictures":1, "Mobile Uploads":2, "Instagram Photos":3}
, nameA = a.name
, weightA = weightTable[nameA] || 100
, nameB = b.name
, weightB = weightTable[nameB] || 100
if(weightA != weightB){
return weightA - weightB;
}else{
return nameA > nameB;
}
}
console.log(sortingAlgorithm.sort(compareFunction));
Using weights for sorting management.
One effective approach is to utilize a custom sort function for sorting arrays. The sort callback function takes two arguments - the first and second elements of the array being compared. Within the callback body, you can implement any logic to determine the comparison result. Returning -1 indicates that the first element should precede the second, 1 means the opposite, and 0 implies equality between the elements.
For alphabetical sorting, compare strings using operators like <, >, <=, or >=. Depending on desired order (ascending or descending), return either -1 or
1</code. To optimize for duplicate items in large data sets, returning <code>0</code can help maintain performance.</p>
<p>To introduce exceptions in alphabetical sorting, assign unique numeric representations to elements. Negative numbers signify exception cases, with smaller values indicating priority. Utilize an if statement to identify and handle exceptions during sorting.</p>
<p><div>
<div>
<pre class="lang-js"><code>
var inputArray = [{
name: "Mobile Uploads"
}, {
name: "Profile Pictures"
}, {
name: "Reports"
}, {
name: "Instagram Photos"
}, {
name: "Facebook"
}, {
name: "My Account"
}, {
name: "Twitter"
}];
var sortedArray = inputArray.slice(0); // create copy for non-destructive sorting
sortedArray.sort(function(a, b) {
var aIndex = 0,
bIndex = 0;
switch (a.name) {
case "Profile Pictures":
aIndex = -3;
break;
case "Mobile Uploads":
aIndex = -2;
break;
case "Instagram Photos":
aIndex = -1;
break;
}
switch (b.name) {
case "Profile Pictures":
bIndex = -3;
break;
case "Mobile Uploads":
bIndex = -2;
break;
case "Instagram Photos":
bIndex = -1;
break;
}
if (aIndex < 0 || bIndex < 0) {
return aIndex < bIndex ? -1 : 1;
} else {
return a.name < b.name ? -1 : 1;
}
});
console.log('Before:');
console.log(inputArray.map(function(v) {
return v.name;
}).join(', '));
console.log('After:');
console.log(sortedArray.map(function(v) {
return v.name;
}).join(', '));
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