Arranging a string array in JavaScript according to an integer array

Question

Arranging a string array in JavaScript according to an integer array

Looking at the provided javascript arrays:

letterArray ['a', 'e', 'i', 'o', 'u']

We also have another array that corresponds to it:

valueArray [12, 22, 7, 7, 3]

The goal is to sort the valueArray into:

[22, 12, 7, 7, 3]

However, the letterArray must be sorted in the same way as well:

['e', 'a', 'i', 'o', 'u']

How can we achieve this sorting?

javascript sorting

Answer 1

Answer №1

To achieve this task, utilize the zipping method, specifically by employing the _.zip function.

// [["a", 12], ["e", 22], ...]
var arr = _.zip(letterArray, valueArray); // Combine arrays.
// Sort
// [["u", 3], ["i", 7] OR ["o", 7], ...]
var sortedArr = _.sortBy(arr, function(val) {
    // Sort based on the value array.
    return val[1];
});
// Retrieve the letter array
// ["u", "i" OR "o", ...]
var newLetterArray = _.pluck(sortedArr, "0");
// Retrieve the value array
// [3, 7, 7, ...]
var newValueArray = _.pluck(sortedArr, "1");

It is worth noting that the presence of duplicate numbers in your example complicates matters and may lead to unpredictability in sorting order. The order of "i" or "o" will vary depending on the browser used.

Answer 2

To achieve this task, utilize the zipping method, specifically by employing the _.zip function.

// [["a", 12], ["e", 22], ...]
var arr = _.zip(letterArray, valueArray); // Combine arrays.
// Sort
// [["u", 3], ["i", 7] OR ["o", 7], ...]
var sortedArr = _.sortBy(arr, function(val) {
    // Sort based on the value array.
    return val[1];
});
// Retrieve the letter array
// ["u", "i" OR "o", ...]
var newLetterArray = _.pluck(sortedArr, "0");
// Retrieve the value array
// [3, 7, 7, ...]
var newValueArray = _.pluck(sortedArr, "1");

It is worth noting that the presence of duplicate numbers in your example complicates matters and may lead to unpredictability in sorting order. The order of "i" or "o" will vary depending on the browser used.

Answer 3

Answer №2

One way to organize your data is by zipping up two arrays into a combined array, like

[[12,'a'], [22, 'e'], [7, 'i'], [7, 'o'], [3, 'u']]

, and then sorting the combined array to easily read off the letters. Another approach is to create your own sorting algorithm and synchronize changes between the integer and letter arrays.

In my opinion, method 1 utilizing a built-in sorting algorithm is more efficient and less labor-intensive than creating a custom sorting algorithm for synchronization purposes.

Answer 4

One way to organize your data is by zipping up two arrays into a combined array, like

[[12,'a'], [22, 'e'], [7, 'i'], [7, 'o'], [3, 'u']]

, and then sorting the combined array to easily read off the letters. Another approach is to create your own sorting algorithm and synchronize changes between the integer and letter arrays.

In my opinion, method 1 utilizing a built-in sorting algorithm is more efficient and less labor-intensive than creating a custom sorting algorithm for synchronization purposes.

Answer 5

Answer №3

// The function myArray.zip takes N arrays and combines them into one array with all pieces interleaved
// Example: [1,2,3].zip([4,5,6],[7,8,9]) -> [ [1,4,7], [2,5,8], [3,6,9] ]
(function(o){
  var zip = function(){
    var argLen = arguments.length;
    var result = new Array(this.length);
    for (var i=this.length-1;i>=0;--i){
    var a = result[i] = [this[i]];
    for (var j=0;j<argLen;++j) a[j+1] = arguments[j][i];
    }
    return result;
  }
  if (Object.defineProperty) Object.defineProperty(o,"zip",{value:zip});
  else o.zip = zip;
})(Array.prototype);

var letters = ['a', 'e', 'i', 'o', 'u'];
var values  = [12, 22, 7, 7, 3];
var valuesAndLetters = values.zip(letters);
// [[12,"a"],[22,"e"],[7,"i"],[7,"o"],[3,"u"]]

var sorted = valuesAndLetters.sort(function(a,b){
  // Sort in descending order, first by value, then by letter
  return a[0]<b[0]?1:a[0]>b[0]?-1:a[1]<b[1]?1:a[1]>b[1]?-1:0;
});
// [[22,"e"],[12,"a"],[7,"o"],[7,"i"],[3,"u"]]

Edit: If you don't have (or want to rely on) defineProperty, and don't want to extend Array.prototype as a fallback, then here's a version of zip that doesn't touch anyone's prototype:

// Combines N arrays into one array with all pieces interleaved
// e.g. Array.zip([1,2,3],[4,5,6],[7,8,9]) -> [ [1,4,7], [2,5,8], [3,6,9] ]
Array.zip = function zip(a0,a1,etc,aN){
  var argLen = arguments.length;
  var result = new Array(a0.length);
  for (var i=a0..length-1;i>=0;--i){
    var a = result[i] = [a0[i]];
    for (var j=1;j<argLen;++j) a[j] = arguments[j][i];
  }
  return result;
};

var letters = ['a', 'e', 'i', 'o', 'u'];
var values  = [12, 22, 7, 7, 3];
var valuesAndLetters = Array.zip(values,letters);
// [[12,"a"],[22,"e"],[7,"i"],[7,"o"],[3,"u"]]

var sorted = valuesAndLetters.sort(function(a,b){
  // Sort in descending order, first by value, then by letter
  return a[0]<b[0]?1:a[0]>b[0]?-1:a[1]<b[1]?1:a[1]>b[1]?-1:0;
});
// [[22,"e"],[12,"a"],[7,"o"],[7,"i"],[3,"u"]]

Answer 6

// The function myArray.zip takes N arrays and combines them into one array with all pieces interleaved
// Example: [1,2,3].zip([4,5,6],[7,8,9]) -> [ [1,4,7], [2,5,8], [3,6,9] ]
(function(o){
  var zip = function(){
    var argLen = arguments.length;
    var result = new Array(this.length);
    for (var i=this.length-1;i>=0;--i){
    var a = result[i] = [this[i]];
    for (var j=0;j<argLen;++j) a[j+1] = arguments[j][i];
    }
    return result;
  }
  if (Object.defineProperty) Object.defineProperty(o,"zip",{value:zip});
  else o.zip = zip;
})(Array.prototype);

var letters = ['a', 'e', 'i', 'o', 'u'];
var values  = [12, 22, 7, 7, 3];
var valuesAndLetters = values.zip(letters);
// [[12,"a"],[22,"e"],[7,"i"],[7,"o"],[3,"u"]]

var sorted = valuesAndLetters.sort(function(a,b){
  // Sort in descending order, first by value, then by letter
  return a[0]<b[0]?1:a[0]>b[0]?-1:a[1]<b[1]?1:a[1]>b[1]?-1:0;
});
// [[22,"e"],[12,"a"],[7,"o"],[7,"i"],[3,"u"]]

Edit: If you don't have (or want to rely on) defineProperty, and don't want to extend Array.prototype as a fallback, then here's a version of zip that doesn't touch anyone's prototype:

// Combines N arrays into one array with all pieces interleaved
// e.g. Array.zip([1,2,3],[4,5,6],[7,8,9]) -> [ [1,4,7], [2,5,8], [3,6,9] ]
Array.zip = function zip(a0,a1,etc,aN){
  var argLen = arguments.length;
  var result = new Array(a0.length);
  for (var i=a0..length-1;i>=0;--i){
    var a = result[i] = [a0[i]];
    for (var j=1;j<argLen;++j) a[j] = arguments[j][i];
  }
  return result;
};

var letters = ['a', 'e', 'i', 'o', 'u'];
var values  = [12, 22, 7, 7, 3];
var valuesAndLetters = Array.zip(values,letters);
// [[12,"a"],[22,"e"],[7,"i"],[7,"o"],[3,"u"]]

var sorted = valuesAndLetters.sort(function(a,b){
  // Sort in descending order, first by value, then by letter
  return a[0]<b[0]?1:a[0]>b[0]?-1:a[1]<b[1]?1:a[1]>b[1]?-1:0;
});
// [[22,"e"],[12,"a"],[7,"o"],[7,"i"],[3,"u"]]

Answer 7

Answer №4

function unique_sort_method(arrayOfIntegers, arrayOfCharacters){
    var min = arrayOfIntegers[0]
    for(index in arrayOfIntegers){
        //implement a custom sorting algorithm
        // that allows you to preserve the original indexes and then map them to the respective character array indexes
    }
}

Answer 8

function unique_sort_method(arrayOfIntegers, arrayOfCharacters){
    var min = arrayOfIntegers[0]
    for(index in arrayOfIntegers){
        //implement a custom sorting algorithm
        // that allows you to preserve the original indexes and then map them to the respective character array indexes
    }
}

Answer 9

Answer №5

Using the method of zipping may seem straightforward, but for a more thorough solution, you can consider utilizing an index array:

var letterArray = ['a', 'e', 'i', 'o', 'u'];
var valueArray = [12, 22, 7, 7, 3];
var indexArray = [0, 1, 2, 3, 4]; // It's recommended to calculate these values dynamically
indexArray.sort(function(a, b) { return valueArray[a] - valueArray[b]; });

In order to obtain an array of letters sorted by their corresponding values, iterate through the indexArray and retrieve the letter at each index.

Answer 10

Using the method of zipping may seem straightforward, but for a more thorough solution, you can consider utilizing an index array:

var letterArray = ['a', 'e', 'i', 'o', 'u'];
var valueArray = [12, 22, 7, 7, 3];
var indexArray = [0, 1, 2, 3, 4]; // It's recommended to calculate these values dynamically
indexArray.sort(function(a, b) { return valueArray[a] - valueArray[b]; });

In order to obtain an array of letters sorted by their corresponding values, iterate through the indexArray and retrieve the letter at each index.

Answer 11

Answer №6

If I were to approach this task differently, I would opt for utilizing a single array containing objects instead of two arrays. By doing so, you have the flexibility to create your own custom sorting function, providing you with maximum control over the data structure.

lettersAndValues = [{letter: 'a', value: 12},
                      {letter: 'e', value: 22},
                      {letter: 'i', value: 7},
                      {letter: 'o', value: 7},
                      {letter: 'u', value: 3}];

function valueComparison(obj1, obj2) {
    if (obj1.value < obj2.value) {
        return 1;
    }
    else if (obj1.value > obj2.value) {
        return -1;
    }
    else { 
        return 0;
    }
}

lettersAndValues.sort(valueComparison);

// => [Object { letter="e", value=22}, 
//     Object { letter="a", value=12},
//     Object { letter="i", value=7}, 
//     Object { letter="o", value=7}, 
//     Object { letter="u", value=3}]

Answer 12

If I were to approach this task differently, I would opt for utilizing a single array containing objects instead of two arrays. By doing so, you have the flexibility to create your own custom sorting function, providing you with maximum control over the data structure.

lettersAndValues = [{letter: 'a', value: 12},
                      {letter: 'e', value: 22},
                      {letter: 'i', value: 7},
                      {letter: 'o', value: 7},
                      {letter: 'u', value: 3}];

function valueComparison(obj1, obj2) {
    if (obj1.value < obj2.value) {
        return 1;
    }
    else if (obj1.value > obj2.value) {
        return -1;
    }
    else { 
        return 0;
    }
}

lettersAndValues.sort(valueComparison);

// => [Object { letter="e", value=22}, 
//     Object { letter="a", value=12},
//     Object { letter="i", value=7}, 
//     Object { letter="o", value=7}, 
//     Object { letter="u", value=3}]

Arranging a string array in JavaScript according to an integer array

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

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