Arrange array of objects based on a specific key

Question

Arrange array of objects based on a specific key

I am currently working with an array of objects that looks like this:

[
  {
    '1485958472927784961': {
      name: 'bruno fiverr',
      points: 6,
      user_id: '1485958472927784961',
      tweets: [Array]
    },
    '1414575563323420679': {
      name: 'ju',
      points: 7,
      user_id: '1414575563323420679',
      tweets: [Array]
    }
  }
]

My goal is to sort this array based on the number of points each user has. I attempted to achieve this using the array.sort method along with a custom function:

var top10 = array.sort(function(a, b) { return a.points > b.points ? 1 : -1; }).slice(0, 10);

However, I keep getting the original array without any changes. Is it possible to accomplish what I'm trying to do?

javascript arrays sorting

Answer 1

Answer №1

If you have an array containing a single object and you need to sort the values by a specific property, follow these steps:

Retrieve the first object in the array using array[0]
Convert the object's values into an array using Object.values
Sort the values in descending order using (a,b) => b.points - a.points
Select the top 10 elements with .slice(0,10)

const array = [
  {
    '1485958472927784961': {
      name: 'bruno fiverr',
      points: 6,
      user_id: '1485958472927784961',
      tweets: [Array]
    },
    '1414575563323420679': {
      name: 'ju',
      points: 7,
      user_id: '1414575563323420679',
      tweets: [Array]
    }
  }
];

const top10 = Object.values(array[0]).sort((a,b) => b.points - a.points).slice(0,10);

console.log(top10);

Answer 2

If you have an array containing a single object and you need to sort the values by a specific property, follow these steps:

Retrieve the first object in the array using array[0]
Convert the object's values into an array using Object.values
Sort the values in descending order using (a,b) => b.points - a.points
Select the top 10 elements with .slice(0,10)

const array = [
  {
    '1485958472927784961': {
      name: 'bruno fiverr',
      points: 6,
      user_id: '1485958472927784961',
      tweets: [Array]
    },
    '1414575563323420679': {
      name: 'ju',
      points: 7,
      user_id: '1414575563323420679',
      tweets: [Array]
    }
  }
];

const top10 = Object.values(array[0]).sort((a,b) => b.points - a.points).slice(0,10);

console.log(top10);

Answer 3

Answer №2

The initial array structure is unnecessary in this case. It would be more efficient to switch to an object format with key-value pairs:

const data = {
  '1485958472927784961': {
    name: 'bruno fiverr',
    points: 6,
    user_id: '1485958472927784961',
    tweets: [],
  },
  '1414575563323420679': {
    name: 'ju',
    points: 7,
    user_id: '1414575563323420679',
    tweets: [],
  },
};

You can then easily extract all the values to form an array of objects, which can be sorted accordingly.

const data = {
  '1485958472927784961': {
    name: 'bruno fiverr',
    points: 6,
    user_id: '1485958472927784961',
    tweets: []
  },
  '1414575563323420679': {
    name: 'ju',
    points: 7,
    user_id: '1414575563323420679',
    tweets: []
  }
}

const sorted = Object.values(data).sort(function(a, b) {
  return a.points > b.points ? 1 : -1;
}).slice(0, 10);

console.log(sorted)

Answer 4

The initial array structure is unnecessary in this case. It would be more efficient to switch to an object format with key-value pairs:

const data = {
  '1485958472927784961': {
    name: 'bruno fiverr',
    points: 6,
    user_id: '1485958472927784961',
    tweets: [],
  },
  '1414575563323420679': {
    name: 'ju',
    points: 7,
    user_id: '1414575563323420679',
    tweets: [],
  },
};

You can then easily extract all the values to form an array of objects, which can be sorted accordingly.

const data = {
  '1485958472927784961': {
    name: 'bruno fiverr',
    points: 6,
    user_id: '1485958472927784961',
    tweets: []
  },
  '1414575563323420679': {
    name: 'ju',
    points: 7,
    user_id: '1414575563323420679',
    tweets: []
  }
}

const sorted = Object.values(data).sort(function(a, b) {
  return a.points > b.points ? 1 : -1;
}).slice(0, 10);

console.log(sorted)

Arrange array of objects based on a specific key

Answer №1

Answer №2

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