I am attempting to change the characters with X and make it look something like this XXXXXT123
This is what I have tried:
var sno = 'TEST123';
alert(sno.slice(0,3).replaceWith('X'));
However, I encountered an error in the console
Uncaught TypeError: sno.slice(...).replaceWith is not a function(anonymous function)
Try this technique (originally suggested by @georg):
sno.replace(/.(?=.{4})/g, "X");
This method will accomplish the task:
sno.replace(/^.+(?=....)/, function (str) { return str.replace(/./g, "X"); });
The initial regular expression /^.+(?=....)/ identifies all characters except for the last four.
Those identified characters are then passed into the custom function. The output of that function determines what the recognized characters should be substituted with.
replace(/./g, "X") swaps out every character with an X.
const key = "RANDOM789";
id.slice(3);
id.slice(-2);
alert(Array(chars * 2).join('Y') + test.slice(5));
To achieve the desired outcome, one could utilize the following algorithm:
let identifier = 'EXAMPLE12345';
String.prototype.customReplace = function(startIndex, endIndex, newText) {
return this.substr(0, startIndex) + this.substr(startIndex, endIndex).replace(/./g, 'X') + this.substr(endIndex);
};
identifier = identifier.customReplace(0, identifier.length - 3, "x");
console.log('modified identifier:', identifier);
Here's a different approach with detailed explanations:
let code = 'CODE123';
let characters = 4;
let beginning = Array(code.length - characters + 1).join('Y'); // Forming an array and combining it with Ys, the length is increased by 1 to include all characters
let ending = code.slice(-4); // Selecting only the last 4 characters
alert(beginning + ending);
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