Analyzing vast datasets from contrasting perspectives

Question

Analyzing vast datasets from contrasting perspectives

Looking for a way to compare two different data storages that contain the same data. The data in question is:

const object1 = {
  "name": "John",
  "age": "30",
  "height": "180 cm",
  "standard": "10th"
}

The comparison should consider the data as identical even if the order of the elements in the object is changed.

I've attempted to hash the data and compare them in batches, but due to the size of the input data, this method is not efficient.

Seeking a more efficient solution to this problem.

javascript json verification

Answer 1

Answer №1

Here is a suggestion you might want to consider:

Give this a shot: console.log(JSON.stringify(obj1).split("").sort().join("") === JSON.stringify(obj2).split("").sort().join(""));

Answer 2

Here is a suggestion you might want to consider:

Give this a shot: console.log(JSON.stringify(obj1).split("").sort().join("") === JSON.stringify(obj2).split("").sort().join(""));

Answer 3

Answer №2

Here is a method to achieve it:

function compareObjects(obj1, obj2) {
  const keys1 = Object.keys(obj1);
  const keys2 = Object.keys(obj2);

  if (keys1.length !== keys2.length) {
    return false;
  }

  for (let key of keys1) {
    if (!obj2.hasOwnProperty(key) || obj1[key] !== obj2[key]) {
      return false;
    }
  }

  return true;
}

const object1 = {
  "name": "John",
  "age": "30",
  "height": "180 cm",
  "class": "10th"
};

const object2 = {
  "class": "10th",
  "age": "30",
  "name": "John",
  "height": "180 cm"
};

console.log(compareObjects(object1, object2));

Answer 4

Here is a method to achieve it:

function compareObjects(obj1, obj2) {
  const keys1 = Object.keys(obj1);
  const keys2 = Object.keys(obj2);

  if (keys1.length !== keys2.length) {
    return false;
  }

  for (let key of keys1) {
    if (!obj2.hasOwnProperty(key) || obj1[key] !== obj2[key]) {
      return false;
    }
  }

  return true;
}

const object1 = {
  "name": "John",
  "age": "30",
  "height": "180 cm",
  "class": "10th"
};

const object2 = {
  "class": "10th",
  "age": "30",
  "name": "John",
  "height": "180 cm"
};

console.log(compareObjects(object1, object2));

Analyzing vast datasets from contrasting perspectives

Answer №1

Answer №2

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