In my code, I am populating an array with sub-arrays of the same type (numbers) and the same size (2). These sub-arrays, when compared using strict equality operator, always return false:
[2, 0] === [2, 0]
I have come up with two ways to compare these sub-arrays:
However, I feel like there might be a better approach to solve this issue. What do you suggest?
When considering my own thought process, I believe it is appropriate to utilize a loop to compare two arrays.
var isTheSame = true;
for (var i in array1) {
if (array1[i] !== array2[i]) isTheSame = false;
}
The mentioned loop functions effectively by returning false if any element varies in type (using three equal signs ===), value, length, or key.
Your second suggestion may not yield the same outcome as the initial one because you have already converted it into a string. What occurs if array1[0] = "true" and array2[0] = true? It will result in true since all elements are now strings, but precise comparison is required, correct?
This represents my personal perspective, and I trust it can be of assistance in some manner.
Best regards, [x]
var arr1=[2,0]; var arr2=[2,0]; arr1.toString() === arr2.toString();
While this may not be the most efficient method, it does seem to get the job done. I believe in opting for concise and easily understandable solutions.
It's worth considering xx3004's observation about potential data loss when converting arrays to strings, especially if you're unsure about the data types within your arrays.
If you want to determine whether two one-dimensional arrays are identical and return true or false, you can use the code snippet provided below. This function is not recursive, but it will work for your current needs.
function testArray(a, b) {
var aLen = a.length;
var bLen = b.length;
if (aLen === bLen) { // check for identical length first
for (var i = 0; i < aLen; i++) {
if (a[i] !== b[i]) {
return false; // members don't match
}
}
return true; // all members matched
}
return false; // not same length
}
Here is the solution I devised...
const compareArrays = (arr1, arr2) => {
const lengthOfArr1 = arr1.length,
lengthOfArr2 = arr2.length;
if (lengthOfArr1 != lengthOfArr2) {
return false;
}
for (let index = 0; index < lengthOfArr1; index++) {
if (arr1[index] !== arr2[index]) {
return false;
}
}
return true;
}
If you're looking for a quick method to compare two arrays, consider using a variation of the toString concept that can handle multidimensional arrays as well:
function checkArraysEquality(arr1, arr2) {
return JSON.stringify(arr1) === JSON.stringify(arr2);
}
checkArraysEquality([[2,3],[7,4],[3,3]], [[2,3],[7,4],[3,3]]) // true
checkArraysEquality([[2,3],[7,4],[3,3]], [[7,4],[2,3],[3,3]]) // false
If you're open to utilizing Underscore, a fantastic tool that I highly regard (possibly even more than jQuery), you have the potential to significantly simplify this code. By flattening the arrays before comparing them, there is no need for nested loops - just a single loop:
function compareArrays( arr1, arr2 ){
var flat = _.zip( _.flatten( arr1 ), _.flatten( arr2 ) );
for( var element in flat ){
if( flat[element][0] !== flat[element][1] ){
return false;
}
}
return true;
}
Additionally, extending this functionality to accommodate any number of arrays should be relatively straightforward.
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