Here's a scenario that showcases the necessity of using ajax: when a radio button is selected, a dynamic drop-down menu appears.
Here's a scenario that showcases the necessity of using ajax: when a radio button is selected, a dynamic drop-down menu appears.
For those who are familiar with or utilize jQuery, here is a method I recommend:
Consider the following HTML structure:
<input type="radio" name="myradio" value="foo" />
<input type="radio" name="myradio" value="bar" />
<input type="radio" name="myradio" value="baz" />
If you have a "your_page.php" file that returns a JSON list to populate a dropdown, follow these steps:
$("input[@name='myradio']").change(function(){
var selected_value = $("input[@name='myradio']:checked").val();
$.getJSON("your_page.php", { value: selected_value }, populate_dropdown);
});
function populate_dropdown(items) {
// The variable "items" contains the dynamically loaded list based on the selected radio button.
// Clear the dropdown, fill it with data, and display it if hidden.
}
Can you provide more details about what you're trying to accomplish?
Are you looking for an instance where clicking on a radio button will display a select option?
If so, you may not need to use ajax.
Here is an example:
<input type="radio" name="YOUR_RADIO" onclick="document.getElementById('selectfield').style.display='';" />
<div id="selectfield" style="display:none">
<select><option>option</option></select>
</div>Best of luck with your project!
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