Can someone help me figure out how to generate a list of numbers based on two criteria?
I need to create this list within the first 50 numbers using JavaScript.
Desired Output:
6, 9, 12, 15... 45
My Attempt:
function getNumbers() {
var result = [];
for (var i = 1; i <= 50; i++) {
if (i % 3 == 0 && i % 10 != 3) {
result.push(i);
}
}
return result.toString();
}
console.log(getNumbers())This solution appears to be in accordance with the specifications - however, it's worth noting that the specifications indicate it should start at 6 rather than 1.
const numbers = [...Array(50).keys()].
filter(num => num !== 0 && num%3 === 0 && !String(num).endsWith("3"))
console.log(numbers)NOTE: If you prefer to skip testing for 0, you can modify [...Array(50).keys()] to [...Array(50).keys()].slice(1)
In order to achieve this, you can implement a conditional check where the modulo of 3 is equal to 0 and the modulo of 10 is not equal to 3. To enhance the code structure, you may integrate this solution with mplungjan's answer; however, I opted to showcase a mathematical approach instead of utilizing the !String(num).endsWith("3") method proposed by mplungjan.
I initiated the iteration at 1 rather than 0 to prevent adding 0 to the array. Additionally, I rectified the return statements for improved clarity.
function getNumbers() {
var result = [];
for (var i = 1; i < 50; i++) {
if (i % 3 === 0 && i % 10 !== 3) {
result.push(i);
}
}
return result;
}
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