I am looking for an array that contains 10 unique random numbers.
Here is the function I have been using:
for (i=0;i<10;i++) {
numbers[i] = Math.floor((Math.random()*10));
for (j=0;j<i;j++){
if (numbers[j]==numbers[i]){duplicate=true;}
}
if (duplicate){i=i-1;}
}
Thank you in advance for your response.
Ensure that all your variables are properly declared:
var x = [], k, l, fail;
It's important to reset the variable "fail" before entering the inner loop:
fail = false;
for (l = 0; l < k; l++)
// ...
On a related note, if you need to store 10 numbers in an array with exactly 10 elements, consider populating the array with numbers from 1 to 10 (or 0 to 9) and then shuffling the array. Following this approach can lead to more predictable performance. If you generate random numbers sequentially, the process could vary greatly in terms of efficiency. As you reach the end of the array, it might require only a few attempts or multiple tries; the randomness of the number sequence adds uncertainty.
To optimize the array filling process, one could start by populating it with numbers ranging from 1 to 10, followed by random shuffling as illustrated below:
let myArray = [1,2,3,4,5,6,7,8,9,10];
//shuffle array
//source: http://stackoverflow.com/a/2450976/1223693
let i = myArray.length, j, temp;
if ( i === 0 ) return false;
while ( --i ) {
j = Math.floor( Math.random() * ( i + 1 ) );
temp = myArray[i];
myArray[i] = myArray[j];
myArray[j] = temp;
}
//completed shuffling
alert(myArray);
The current approach may be sluggish due to its inner loop design and the possibility of producing incorrect numbers multiple times before reaching a valid output.
Are you looking to generate an array consisting of 10 elements, each holding a random number between 0 and 9, with none of the numbers repeating? Essentially, you want to shuffle the numbers 0-9 within these 10 elements?
If so, the solution is simple - initialize the array and then proceed to shuffle it using the following code:
// Function for shuffling array
function shuffleArray(arr) {
for(let j, x, i = arr.length; i; j = Math.floor(Math.random() * i), x = arr[--i], arr[i] = arr[j], arr[j] = x);
return arr;
}
// Initialize the array:
let myArray = [];
for (let i = 0; i < 10; i++) {
myArray.push(i);
}
// Shuffle the array:
myArray = shuffleArray(myArray);
A more streamlined approach could be:
const numbers = [9, 8, 7, 6, 5, 4, 3, 2, 1, 0].sort(
function(){return Math.random() - 0.5});
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