ALSO, various criteria

Question

ALSO, various criteria

function findLogicalAND(){
  let result;
  let index;
  for (index = 0; index < arguments.length; index++){
    result =  arguments[index] && arguments[index+1];
  }
  return result;
}

console.log(findLogicalAND(true, true, false, false));

I want to run the code: true&&true&&false&&false and get false.

Any suggestions on how to achieve this in JavaScript? Thanks

javascript function

Answer 1

Answer №1

Utilize the Array.prototype.every method on all the provided arguments to verify if they are all true;

function checkIfAllTrue(...args) {
  if(args.length === 0) return false; // return false if no argument is passed
  return args.every(Boolean);
}

console.log(checkIfAllTrue(true, true, false)); // expected output: false
console.log(checkIfAllTrue(true, true, true)); // expected output: true

Answer 2

Utilize the Array.prototype.every method on all the provided arguments to verify if they are all true;

function checkIfAllTrue(...args) {
  if(args.length === 0) return false; // return false if no argument is passed
  return args.every(Boolean);
}

console.log(checkIfAllTrue(true, true, false)); // expected output: false
console.log(checkIfAllTrue(true, true, true)); // expected output: true

Answer 3

Answer №2

To get started, you should:

Begin with setting logicalAnd to true
Update logicalAnd using the logical AND operator instead of extracting values from arguments

The simplest modification is:

function andMultipleExpr(){
    let logicalAnd = true; // ***
    let i;
    for (i = 0; i < arguments.length; i++){
        logicalAnd = logicalAnd && arguments[i]; // ***
    }
    return logicalAnd;
}
console.log(andMultipleExpr(true, true, false, false));

However, mbojko's technique includes the benefit of short-circuiting, which stops the loop at the first falsy value, a commendable approach.

Since ES2015+, it's advisable to use a rest parameter in place of arguments, along with a for-of loop:

function andMultipleExpr(...flags) {
    let logicalAnd = true;
    for (const flag of flags) {
        logicalAnd = logicalAnd && flag;
    }
    return logicalAnd;
}
console.log(andMultipleExpr(true, true, false, false));

You can also implement short-circuiting following mbojko's method

function andMultipleExpr(...flags) {
    for (const flag of flags) {
        if (!flag) {
            return false;
        }
    }
    return true;
}
console.log(andMultipleExpr(true, true, false, false));

While some may suggest using reduce, Archie's implementation of every proves to be more efficient (especially when utilizing .every(flag => flag) due to non-strict comparisons).

Answer 4

To get started, you should:

Begin with setting logicalAnd to true
Update logicalAnd using the logical AND operator instead of extracting values from arguments

The simplest modification is:

function andMultipleExpr(){
    let logicalAnd = true; // ***
    let i;
    for (i = 0; i < arguments.length; i++){
        logicalAnd = logicalAnd && arguments[i]; // ***
    }
    return logicalAnd;
}
console.log(andMultipleExpr(true, true, false, false));

However, mbojko's technique includes the benefit of short-circuiting, which stops the loop at the first falsy value, a commendable approach.

Since ES2015+, it's advisable to use a rest parameter in place of arguments, along with a for-of loop:

function andMultipleExpr(...flags) {
    let logicalAnd = true;
    for (const flag of flags) {
        logicalAnd = logicalAnd && flag;
    }
    return logicalAnd;
}
console.log(andMultipleExpr(true, true, false, false));

You can also implement short-circuiting following mbojko's method

function andMultipleExpr(...flags) {
    for (const flag of flags) {
        if (!flag) {
            return false;
        }
    }
    return true;
}
console.log(andMultipleExpr(true, true, false, false));

While some may suggest using reduce, Archie's implementation of every proves to be more efficient (especially when utilizing .every(flag => flag) due to non-strict comparisons).

Answer 5

Answer №3

The implementation of early returns can significantly enhance both the efficiency and brevity of code:

function checkAllArguments() {
  for (let i = 0; i < arguments.length; i++) {
    if (!arguments[i]) {
      return false;
    }
  }

  return true;
}

Answer 6

The implementation of early returns can significantly enhance both the efficiency and brevity of code:

function checkAllArguments() {
  for (let i = 0; i < arguments.length; i++) {
    if (!arguments[i]) {
      return false;
    }
  }

  return true;
}

Answer 7

Answer №4

I found a concise method utilizing ES6 and the Array.prototype.reduce function.

let andMultipleExpr = (...args) => args.reduce((a, b) => a && b);

console.log(andMultipleExpr(true, true, false, false));

If you want to learn more about how the reduce function works, check out this article on MDN

Answer 8

I found a concise method utilizing ES6 and the Array.prototype.reduce function.

let andMultipleExpr = (...args) => args.reduce((a, b) => a && b);

console.log(andMultipleExpr(true, true, false, false));

If you want to learn more about how the reduce function works, check out this article on MDN

Answer 9

Answer №5

If you utilize Array#every method, it is possible to retrieve the final value.

This particular method returns the outcome of logical AND operation using &&.

With this streamlined approach, a shortcut is created for detecting the first false value. Consequently, the looping process halts at that point.

function andMultipleExpr(...args) {
    var result; // customizable return value for empty arguments
    args.every(v => result = v);
    return result;
}

console.log(andMultipleExpr(true, true, false, false));
console.log(andMultipleExpr(true, true, 1, 2));
console.log(andMultipleExpr(true, 0, 1, 2));

Answer 10

If you utilize Array#every method, it is possible to retrieve the final value.

This particular method returns the outcome of logical AND operation using &&.

With this streamlined approach, a shortcut is created for detecting the first false value. Consequently, the looping process halts at that point.

function andMultipleExpr(...args) {
    var result; // customizable return value for empty arguments
    args.every(v => result = v);
    return result;
}

console.log(andMultipleExpr(true, true, false, false));
console.log(andMultipleExpr(true, true, 1, 2));
console.log(andMultipleExpr(true, 0, 1, 2));

Answer 11

Answer №6

Maybe you're curious about what went awry with the loop:

for (i = 0; i < arguments.length; i++){
  logicalAnd =  arguments[i] && arguments[i+1];
}

This loop calculates the && of the last two items it comes across. Ideally, it should combine the last two elements of the array, which is not what you actually need.
Furthermore, at the end of the loop i=arguments.length-1, it checks the last element of the array, and i+1 refers to the element "after" the last one, which is undefined. In terms of logical relationships, this is considered false, but && outputs the value itself in such scenarios, resulting in the function always returning undefined (this detail could have been mentioned in the question).

Documentation

expr1 && expr2: If expr1 can be converted to true, returns expr2; otherwise, returns expr1.

arr=[true];
console.log("your case:",arr[0] && arr[1]);

console.log("1 && 2:", 1 && 2);

A better approach would be to use logicalAnd as an accumulator that stores the result of combining all previous elements using &&. You can optimize by considering that if any partial && calculation results in

false</code, the final output will also be false. Therefore, the loop can terminate early:</p>

<p><div>
<div>
<pre class="lang-js"><code>function andMultipleExpr(){
    let logicalAnd = arguments[0] || false;
    for (let i = 1; i < arguments.length && logicalAnd; i++){
        logicalAnd = logicalAnd && arguments[i];
    }
    return logicalAnd;
}

console.log("():",andMultipleExpr());
console.log("(false):",andMultipleExpr(false));
console.log("(true):",andMultipleExpr(true));
console.log("(true,true):",andMultipleExpr(true,true));
console.log("(true, true, false, false):",andMultipleExpr(true, true, false, false));

Answer 12

Maybe you're curious about what went awry with the loop:

for (i = 0; i < arguments.length; i++){
  logicalAnd =  arguments[i] && arguments[i+1];
}

This loop calculates the && of the last two items it comes across. Ideally, it should combine the last two elements of the array, which is not what you actually need.
Furthermore, at the end of the loop i=arguments.length-1, it checks the last element of the array, and i+1 refers to the element "after" the last one, which is undefined. In terms of logical relationships, this is considered false, but && outputs the value itself in such scenarios, resulting in the function always returning undefined (this detail could have been mentioned in the question).

Documentation

expr1 && expr2: If expr1 can be converted to true, returns expr2; otherwise, returns expr1.

arr=[true];
console.log("your case:",arr[0] && arr[1]);

console.log("1 && 2:", 1 && 2);

A better approach would be to use logicalAnd as an accumulator that stores the result of combining all previous elements using &&. You can optimize by considering that if any partial && calculation results in

false</code, the final output will also be false. Therefore, the loop can terminate early:</p>

<p><div>
<div>
<pre class="lang-js"><code>function andMultipleExpr(){
    let logicalAnd = arguments[0] || false;
    for (let i = 1; i < arguments.length && logicalAnd; i++){
        logicalAnd = logicalAnd && arguments[i];
    }
    return logicalAnd;
}

console.log("():",andMultipleExpr());
console.log("(false):",andMultipleExpr(false));
console.log("(true):",andMultipleExpr(true));
console.log("(true,true):",andMultipleExpr(true,true));
console.log("(true, true, false, false):",andMultipleExpr(true, true, false, false));

ALSO, various criteria

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

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