After successfully posting a tweet, I have not heard back from Twitter

My objective is to achieve the following on click:

  1. Share the URL and text on Twitter in a popup window

  2. Receive a response from Twitter indicating whether the tweet was successful or failed

  3. Close the popup window after the tweet is successfully posted or when the user chooses to close it

The challenges I am facing include:

  1. Not receiving any response from Twitter regarding the success or failure of the tweet

  2. The popup window remains open even after the tweet has been successfully posted

I have explored various solutions on Stack Overflow without success so far

The code below is within the HTML body tag:


    <script>
        window.twttr = (function(d, s, id) {
          var js, fjs = d.getElementsByTagName(s)[0],
            t = window.twttr || {};
          if (d.getElementById(id)) return t;
          js = d.createElement(s);
          js.id = id;
          js.src = "https://platform.twitter.com/widgets.js";
          fjs.parentNode.insertBefore(js, fjs);

          t._e = [];
          t.ready = function(f) {
            t._e.push(f);
          };

          return t;
        }(document, "script", "twitter-wjs"));
    </script>

Function to open in a popup:


function share_to_twitter(sParamUrl, sParamText, iParamWinWidth, iParamWinHeight) {
    var iWinTop = (screen.height / 2) - (iParamWinHeight / 2);
    var iWinLeft = (screen.width / 2) - (iParamWinWidth / 2);
    
    window.open('http://twitter.com/intent/tweet?url='+encodeURIComponent(sParamUrl) + '&text=' + sParamText,'top=' + iWinTop + ',left=' + iWinLeft + ',toolbar=0,status=0,width=' + iParamWinWidth + ',height=' + iParamWinHeight, '_blank');
} 

share_to_twitter('https://example.com','Text to tweet', 640, 480);

Receiving response from Twitter and taking necessary action:


twttr.ready(function (twttr) {
    twttr.events.bind('tweet', function(event) {
       alert(event);
       /*Example:
        if(event == 'success'){
          window.close();
       }
       else{
         //Do something else
       */
   });
});

Answer №1

When I clicked directly on the Twitter link instead of opening it in a popup, I finally received a response:

<a href = "http://twitter.com/share?text=text example here&url=http://sample.com" target = "_blank">Click here to share</a>

Although, as noted on this Twitter forum thread, a Twitter representative explained:

Regrettably, there is no event triggered when the tweet is actually posted, only when the popup is opened. The analytics code you're currently using may be the most accurate solution.

However, another Twitter staff member recommends utilizing the search or timeline API to verify if the message was successfully shared. Check out the details here:

You'd need to have the username and then leverage the search or timeline API to check the post status.

The OP's code does not provide confirmation if the tweet went through. To receive feedback on a tweeted message from Twitter, follow these steps,

Insert this code within the HTML body tag just after the <body> tag:

<script>

    window.twttr = (function(d, s, id) {
      var js, fjs = d.getElementsByTagName(s)[0],
        t = window.twttr || {};
      if (d.getElementById(id)) return t;
      js = d.createElement(s);
      js.id = id;
      js.src = "https://platform.twitter.com/widgets.js";
      fjs.parentNode.insertBefore(js, fjs);

      t._e = [];
      t.ready = function(f) {
        t._e.push(f);
      };

      return t;
    }(document, "script", "twitter-wjs"));
</script>

Then, incorporate the customized link for visitors to click and share on Twitter:

<a href = "http://twitter.com/share?text=text goes here&url=http://example.com" target = "_blank">Click here to tweet</a>

Furthermore, the following code handles responses from Twitter sharing:

twttr.ready(function (twttr) {
    twttr.events.bind(
        'tweet',
    twitter_share_callback);
});

function twitter_share_callback(response) {
    console.log(response);
}   

Remember: The mentioned code delivers an immediate response once the visitor triggers the tweet link. It provides feedback regardless of whether the tweet was successful, offering limited insight into its posting status.

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